W=mgh
W=(6)(9.8)(4)
W= 235.2J
Answer:
θ = 28.9°
Explanation:
We are given;
Wavelength; λ = 602nm = 602 x 10^(-9) m
Lines per centimetre = 7000 /cm = 700000 /m
Thus, the distance between 2 adjacent lines is;
d = 1/700000 = 1.43 x 10^(-6) m
The angle at which diffracted light is formed is given by the formula
mλ = d sinθ
Where;
m is the mth order of the diffraction
λ is the wavelength of the incident light
d is the distance separating the centres of 2 adjacent slits
θ is the angle at which diffraction occurs
From the question, m is 1 because it says first order.
Thus, plugging in the relevant values into mλ = d sinθ, we have;
1 x 602 x 10^(-9) = 1.43 x 10^(-6) sinθ
sinθ = 602 x 10^(-9)/(1.43 x 10^(-6))
sinθ = 0.42098
θ = sin^(-1) 0.42098
θ = 28.9°
<span>Δ</span>E = q + w
q = heat (quantity of)
q and w can be positive or negative depending on if work/heat is being absorbed/done on the system or released/done by the system
Answer:
[ 2.67 , 1 ] m
Explanation:
Given:-
- The side lengths of the rods are as follows:
a = 4 m , b = 4 m , c = 5 m
a = Base , b = Perpendicular , c = Hypotenuse
- All rods are made of same material with uniform density. With
Find:-
Find the coordinates of the center of mass of the triangle.
Solution:-
- The center of mass of any triangle is at the intersection of its medians.
- So let’s say we have a triangle with vertices at points (0,0) , (a,0) , and (0,b).
- Median from (0,0) to midpoint (a/2,b/2) of opposite side has equation:
bx−ay=0
- Median from (a,0) to midpoint (0,b/2) of opposite side has equation:
bx+2ay=ab
- Median from (0,b) to midpoint (a/2,0) of opposite side has equation:
2bx+ay=ab
- Solve all three equations simultaneously:
bx−ay=0 , bx = ay
ay + 2ay = ab , 3ay = ab , y = b/3
bx = b/3
x = a / 3
- So the distance from the median to each leg of the triangle is 1/3 length of other leg.
- So the coordinates of the centroid for right angle triangle would be:
[ 2a/3 , b/3 ]
[ 2.67 , 1 ] m
