The mass of the planet Gallifrey is 8 times the mass of the Earth.
- let the gravitational field of Earth = g
- let the radius of the Earth = R
- gravitational field of Gallifrey = 2g
- radius of Gallifrey = 2R
<h3>What is gravitational potential energy?</h3>
- This is the work done in moving an object to a certain distance against gravitational field.
The gravitational field strength of the Earth is given as follows;
The gravitational field strength of the Planet Gallifrey is calculated as follows;
Thus, the mass of the planet Gallifrey is 8 times the mass of the Earth.
Learn more about gravitational field strength here: brainly.com/question/14080810
<h3><u>Answer</u>;</h3>
B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.
<h3><u>Explanation;</u></h3>
- <em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
- <em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
- <em><u>Filament movement starts at the region or zone where thin and thick filaments overlap. </u></em>
- <em><u>Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.</u></em>
<h3><u>Answer;</u></h3>
a) 5.00 x 10^8 J
<h3><u>Explanation;</u></h3>
The work done to move the sailboat is calculated through the equation;
W = F x d
where F is force and d is the distance.
Substituting the known values from the given above,
W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)
= 5.00 x 10⁸ J
Thus, the work done is <u>5.00 x 10⁸Joules</u>
Answer:
the terminal velocity of 14 nested coffee filters is 3.2 m/s
Explanation:
Given the data in the question;
we know that;
The terminal velocity is proportional to the square root of weight.
v ∝ √W
v = k√W
the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged
v/√W = constant
v₂/√W₂ = v₁/√W₁
v₂ = v₁√(W₂ / W₁ )
given that;
v₁ = 0.856 m/s,
W₂ = 14W₁; meaning 14 coffee filters have 14 times the weight of a single coffee filter
so we substitute
v₂ = 0.856 √(14W₁ / W₁ )
v₂ = 0.856 √( 14( W₁/W₁)
v₂ = 0.856 √( 14(1)
v₂ = 0.856 √( 14 )
v₂ = 0.856 × 3.741657
v₂ = 3.2 m/s
Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s
