<span>The calculation of quantities in chemical equations are called Stoichiometry. Stoichiometry is a branch of chemistry which deals with relative quantities of reactants and products in chemical reactions. The correct answer is 'Stoichoimetry'. I hope this helps you. </span>
If this is just a general question it seems to vary from about 4.5g to 5g. Is there more data to the question?
The given question is incomplete . The complete question is :
In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?
a. The giving atom and receiving atom are both negatively charged
b. The giving atom is now positively charged and the receiving atom is now negatively charged.
c. The giving and receiving atom are both positively charged
d. The giving atom is now negatively charged and the receiving atom is now positively charged.
Answer: The giving atom is now positively charged and the receiving atom is now negatively charged.
Explanation:
Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Thus when one electron moves from one atom to another, the metal acquires a positive charge and the non metal acquires negative charge.
For example:
is formed by transfer of one electron from sodium to chlorine , thus forming
and 
Answer:
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Explanation:
<em>Telophase is the process that separates the duplicated genetic material carried in the nucleus of a parent cell into two identical daughter cells.</em>
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The balanced reaction equation for the combustion of butane is as follows;
C₄H₁₀ + 13/2O₂ ---> 4CO₂ + 5H₂O
the limiting reactant in this reaction is C₄H₁₀ This means that all the butane moles are consumed and amount of product formed depends on the amount of C₄H₁₀ used up.
stoichiometry of C₄H₁₀ to H₂O is 1:5
mass of butane used - 6.97 g
number of moles - 6.97 g / 58 g/mol = 0.12 mol
then the number of water moles produced - 0.12 mol x 5 = 0.6 mol
Therefore mass of water produced - 0.6 mol x 18 g/mol = 10.8 g