How many neutrons does element X have if its atomic number is 32 and its mass number is 75?

uranium hexafluoride is a solid at room temperature, but it boils at $56^o C$.determine the density of uranium hexafluoride at

PSYCHO15rus [73]

<span>If it is known that at 60 °C and 745 torr UF₆ is present only as a gas then we can make the assumption that:

</span>(n/V) = P/RT = (745 torr)/(62.36 L-torr/mol•K)(337 K) = 0.0354 mol/L
Therefore the density will be:
<span>
Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0125 g/cm³
</span>

6 0

3 years ago

Under what circumstances can an atom emit a photon

blagie [28]

Answer:

Here

Explanation:

When the atom absorbs energy, it can move to a higher energy state, or excited state. Under what circumstances can an atom emit a photon? A photon is emitted when an atom moves from an excited state to its ground state or to a lower-energy excited state.

3 0

3 years ago

Compound A is an organic compound which contains Carbon, Hydrogen and Oxygen. When 0.240g of the vapour of A is slowly passed ov

vesna_86 [32]

(a) In this section, give your answers to three decimal places.

(i)

Calculate the mass of carbon present in 0.352 g of CO

2

.

Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g

of

A

.

(ii)

Calculate the mass of hydrogen present in 0.144 g of H

2

O.

Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g

of

A

.

(iii)

Use your answers to calculate the mass of oxygen present in 0.240 g of

A

Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g

of

A

(b)

Use your answers to

(a)

to calculate the empirical formula of

A

thank you

hope it helpsss

4 0

4 years ago

1.) What would happen to the rock cycle if erosion did not occur?

ohaa [14]

Sedimentary rock would not form

3 0

3 years ago

In looking at the bolded atoms in the answer choices, which pair consists of molecules having the same geometry? hints in lookin

Rzqust [24]

Correct Answer: CH2CCI2 and CH2CH2.

Reason:
Structure of compound depends on the hybridization of central atom. In both of the above molecules (i.e. CH2CCL2 and CH2CH2). Central atom i.e. carbon is sp^2 hybridized. Thus 3 hybridized orbitals of 'C' is involved in sigma bonding. Further, these orbitals are placed spatially at an angle of $120^{0}$ . The un-hybridized 2pz orbital of 'C' is involved in pi-bonding. Due to this, both of the above molecules possess a triangular planner geometry.

5 0

3 years ago

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