For the reaction;
N2(g) + O2(g) = 2NO(g)
Kp = pNO²/ pN₂pO₂; (No units)
where;
pNO is the partial pressure of NO;
pN₂ is the partial pressure of nitrogen
pO₂ is the partial pressure of Oxygen
The equilibrium constant Kp is deduced from the balanced chemical equation for a reversible reaction, NOT experimental data as is the case for rate expressions in kinetics.
Kp changes with temperature considerably changing the position of an equilibrium, and, at a constant temperature, and therefore constant K, the position of an equilibrium can change significantly depending on relative concentrations/pressures of 'reactants' and 'products'.
Because M = mol/L or mL. 15.0 x 0.350/42.0 = M
Answer:
velocity
Explanation:
because he is going 30 miles west
Answer:
C₆H₆
Explanation:
We need to find the molecular formula of a compound of carbon (C) and hydrogen (H), so what <em>we need to find out is the number of atoms of C and of H in the molecule.</em> We know:
- molar mass = 78.1 g/mol
- C% = 92.3% = 92.3 g C / 100 g compound
So, in 1 mol of compound, 92.3% of the mass corresponds to Carbon:
<u>mass of C / mol of compound</u> = molar mass × C% = 78.1 g/mol × 92.3/100 = <u>72.1 g/mol</u>
<u>moles of C</u> = mass C / molar mass C = 72.1 g / 12.011 g/mol
moles of C = 6 moles of C per mol of compound
If 72.1 g in a mol of compound are Carbon atoms, the difference between the molar mass and the mass of Carbon atoms will correspond to H atoms in 1 mol of compound:
<u>mass of H / mol of compound</u> = molar mass - mass of C/mol
mass of H = 78.1 g / mol - 72.1 g /mol = <u>6.0 g/mol of compound</u>
<u>moles of H</u> = mass H / molar mass H = 6.0 g / 1.008 g/mol
moles of H = 6.0 moles of H per mol of compound
<em>So</em><em> one mol of compound has 6 moles of C and 6 moles of H.</em>
The molecular formula is then written as C₆H₆
