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nikitadnepr [17]
3 years ago
6

What is the primary technique for determining the absolute age of rock

Physics
1 answer:
jekas [21]3 years ago
7 0
<span>D. measuring radioactive decay of element isotopes </span>
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A circuit has a resistance of 10ohmsband a current of 42 amps.caculate the voltage
Anon25 [30]
R=U/I so
U=RxI
U= 10 x 42
U= 420 volts
3 0
3 years ago
The efficiency of a light source is the percentage of its energy input that gets radiated as visible light. if some of the blue
Anestetic [448]

The efficiency of a light source is the percentage of its energy input that gets radiated as visible light if some of the blue light in an led is used to cause a fluorescent material to glow the overall efficiency of the LED decreases.

How efficient is LED?

Different wavelengths that correlate to different visible colours are used in LED light therapy. Various shades pierce the skin at different rates.

  1. Your skin's outermost layer is impacted by blue light.
  2. Yellow light is more enveloping.
  3. Red light penetrates your skin more deeply.
  4. The deepest penetrating light is near-infrared.

Different LED hues have various effects. For instance, according to experts red LED light therapy has the potential to reduce inflammation and boost collagen formation, which declines with age and is crucial for maintaining youthful-looking skin.

Acne-causing bacteria may be destroyed by a blue LED light therapy (P. acnes).

Hence the answer is the overall efficiency of the LED decreases.

Learn more about wavelength here,

brainly.com/question/1263539

# SPJ4

7 0
2 years ago
Please please help me
Illusion [34]

Answer:

amitude doesnt change

Explanation:

6 0
3 years ago
Two point charges are fixed on the y axis: a negative point charge q1 = -25 μC at y1 = +0.18 m and a positive point charge q2 at
dedylja [7]

Answer:

50.91 \mu C

Explanation:

The magnitude of the net force exerted on q is known, we have the values and positions for q_{1} and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted byq_{1} on q. Then we can know the magnitude of the force exerted by q_{2} about q, finally this will allow us to know the magnitude of q_{2}

q_{1} exerts a force on q in +y direction, and q_{2} exerts a force on q in -y direction.

F_{1}=\frac{kq_{1} q }{d^2}\\F_{1}=\frac{(8.99*10^9)(25*10^{-6}C)(8.4*10^{-6}C)}{(0.18m)^2}=58.26 N\\

The net force on q is:

F_{T}=F_{1} - F_{2}\\25N=58.26N-F_{2}\\F_{2}=58.26N-25N=33.26N\\\mid F_{2} \mid=\frac{kq_{2}q}{d^2}

Rewriting for q_{2}:

q_{2}=\frac{F_{2}d^2}{kq}\\q_{2}=\frac{33.26N(0.34m)^2}{8.99*10^9\frac{Nm^2}{C^2}(8.4*10^{-6}C)}=50.91*10^{-6}C=50.91 \mu C

8 0
3 years ago
12. Where is the Moon? If you see it, describe its location and appearance. ​
garri49 [273]
Do you mean in general or in a piece of paper?
3 0
3 years ago
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