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emmasim [6.3K]
3 years ago
6

When electrons are removed from the outermost shell of a calcium atom, the atom becomesA. an anion that has a larger radius than

the atomB. an anion that has a smaller radius than the atom.C. a cation that has a larger radius than the atom.D. a cation that has a smaller radius than the atom.
Physics
2 answers:
hoa [83]3 years ago
6 0

Answer:

D: a cation that has a smaller radius than the atom

Explanation:

Got it right on edg :)

Free_Kalibri [48]3 years ago
3 0

Answer:

D. a cation that has a smaller radius than the atom.

Explanation:

When electrons are removed from the outermost shell of a calcium atom, the atom becomes a cation that has a smaller radius than the atom.

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Identify the volume units that are greater than one liter
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There are a lot of volume units, most specifically in English units, that are greater than one liter. The following are as follows:

gallon, which is equal to 4.54 liters
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Also included are metric units which are dekaliter onwards.
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3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
abruzzese [7]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

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\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

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8 0
4 years ago
Read 2 more answers
A student fills a tank of radius r with water to a height of h1 and pokes a small, 1.0 cm diameter hole at a distance h2 from th
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when a hole is made at the bottom of the container then water will flow out of it

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from above equation we can say that speed at the top layer is almost negligible.

v_1 = 0

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\rho g h = \frac{1}{2} \rho v^2

v = \sqrt{2 g h}

here we have

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v = \sqrt{2* 9.8 * 0.47}

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7 0
3 years ago
A 66-kg diver jumps off a 9.7-m tower. (a) Find the diver's velocity when he hits the water. (b) The diver comes to a stop 2.0 m
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Answer:

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(b)

F = ma.................... Equation 2

Where F = force exerted on the diver, m = mass of the diver, a = acceleration of the diver below the water surface.

Also using

v² = u² + 2as ............ Equation 3

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Substitute into equation 3

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Also given: m = 66 kg,

Substitute into equation 3

F = (-47.58)(66)

F = -3140.28

Note: The Force is negative because it act against the motion of the diver.

Hence the net force exerted on the diver while in the water = -3140.28 N.

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