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Vinvika [58]
3 years ago
14

Example: A wooden crate with mass 100kg is at rest on a stone floor. You know that the coefficients of kinetic and static fricti

on are: μs=0.5 and μk=0.4. A) What is the minimum horizontal force F need to just get the crate moving?
Physics
1 answer:
alexgriva [62]3 years ago
7 0

Answer

Any force greater 490N

Explanation

The force required just to make an object slide over a rough horizontal surface is any force greater that the static friction which given by;

F=\mu_s mg.............(1)

Given;

\mu_s=0.5\\m=100kg\\g=9.8m/s^2

Hence;

F = 0.5 x 100 x 9.8

F = 490N.

We will only need the coefficient of kinetic friction if we were asked to find the force required to keep the object moving uniformly. Usually, the force needed to keep an object moving uniformly over a rough surface is lesser that which is needed to start its motion.

In this problem, we were only asked to find the minimum force required to make the object move which we have done.

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9. A pendulum bob is made with a ball filled with water. What would happen to the frequency of vibration of this pendulum if a h
Ilya [14]

Answer:

The frequency of vibration will be unchanged.

Explanation:

The frequency of oscillation of a simple pendulum is given by

f = \dfrac{1}{2 \pi}\sqrt{\dfrac{g}{L}}

where, g is the acceleration due to gravity and L is the length of the pendulum.

It can be seen from the formula that the frequency of the pendulum is independent of the mass.

Thus, the frequency of vibration will be same.

6 0
3 years ago
What is the percentage of the incoming solar radiation from the top of the atmosphere the gets reflected right back out into spa
san4es73 [151]

Answer: We can define the solar constant as a measure of the luminous flux density.

Explanation:

The solar constant or solar constant is the amount of energy radiated at the upper limit of the Earth's atmosphere per unit time perpendicular to the unit surface, at the Earth's mean distance from the sun. Amounts to 1367.7 W / m² ± 6 W / m². The sun's constant includes all kinds of electromagnetic radiation, not just visible light. The average value is 1,368 kW / m2 and changes slightly with solar cycles. The amount of these constant changes over one year and has different benefits.

4 0
3 years ago
A ball is thrown off the top of a building and lands on the ground below.
natita [175]

Answer:

Mass and velocity.

Explanation:

Kinetic energy <u>is the energy that an object has due to its movement</u>, mathematically it is represented as follows:

K=\frac{1}{2} mv^2

where m is the mass of the object, and v is its velocity at a given point in time.

So we can see that to find the kinetic energy just before the ball hits the gound, we need the quantities:

  • mass of the ball
  • velocity of the ball before it hits the ground

With the knowledge of these two quantities the kinetic energy of the ball  before touching the gound can be determined.

4 0
3 years ago
Choose all correct sentences Group of answer choices The power is maximum when the value of the impedance is greater than the va
Illusion [34]

Answer:

True  b and c

Explanation:

In an RLC circuit the impedance is

         Z = \sqrt{[R^{2} + ( (wL)^{2} + (\frac{1}{wC})^{2} ]     }

examine the different phrases..

a) False. The maximum impedance is the value of the resistance  

b) True. Resonance occurs when  

              (wL)² + (1 / wC)² = 0

               w² = 1 / LC

c) True. In resonance the impedance is the resistive part and the power is maximum  

d) False. In resonance the inductive and capacitive part cancel each other out  

e) False. The impedance is always greater outside of resonance, but at the resonance point they are equal

6 0
3 years ago
We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
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