Answer:
18 m
Explanation:
Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s
solving for the final velocity, v
v = a * t
v = 4 m/s^2 * 3 s
v = 12 m / s
Solving for the average velocity. avg v
avg v = (vo + v) / 2
avg v = (0 m / s + 12 m/s) / 2
avg v = 6 m / s
Solving for the distance traveled after 3 s
d = avg v * t
d = 6 m / s * 3 s
d = 18 meters
In the first 3s the car travels 18 meters.
Answer:
As wind or an ocean current moves, the Earth spins underneath it. ... The Coriolis effect bends the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere.
Explanation:
The Coriolis effect causes winds and currents to form circular patterns.
(a)
Electronic configuration is given as follows:
![[Kr]4d^{3}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B3%7D)
Since, this is the electronic configuration of ion with+3 that means 3 electrons are removed. On adding the 3 electrons, the electronic configuration of neutral atom can be obtained.
Thus, electronic configuration of neutral atom is
.
The atomic number of Kr is 36, thus, total number of electrons become 36+6=42.
This corresponds to element: molybdenum. Thus, the tripositive atom will be
.
(b) The given electronic configuration is
.
The atomic number of Kr is 36, thus, total number of electrons become 36+4=40.
This corresponds to element zirconium, represented by symbol Zr.
Answer:
a). ![P=78.4W](https://tex.z-dn.net/?f=P%3D78.4W)
b). ![P=392kPa](https://tex.z-dn.net/?f=P%3D392kPa)
c.) It must be at the bottom
Explanation:
Given:
Volume flow ![V_f=2.0x10^{-4}m^3/s](https://tex.z-dn.net/?f=V_f%3D2.0x10%5E%7B-4%7Dm%5E3%2Fs)
Well depp ![h=40.m](https://tex.z-dn.net/?f=h%3D40.m)
a.
The power output of the pum
![W=F*d](https://tex.z-dn.net/?f=W%3DF%2Ad)
![F=m*g](https://tex.z-dn.net/?f=F%3Dm%2Ag)
![m=p*V=1000kg/m^3*2.0x10^{-4}m^3}=0.2Kg](https://tex.z-dn.net/?f=m%3Dp%2AV%3D1000kg%2Fm%5E3%2A2.0x10%5E%7B-4%7Dm%5E3%7D%3D0.2Kg)
![W=m*g*d=0.2kg*9.8m/s^2*40.0m=78.4kg*m^2/s^2](https://tex.z-dn.net/?f=W%3Dm%2Ag%2Ad%3D0.2kg%2A9.8m%2Fs%5E2%2A40.0m%3D78.4kg%2Am%5E2%2Fs%5E2)
![W=78.4J](https://tex.z-dn.net/?f=W%3D78.4J)
![P=\frac{W}{t}=\frac{78.4J}{1s}=78.4W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D%3D%5Cfrac%7B78.4J%7D%7B1s%7D%3D78.4W)
b.
The pressure of difference the pum
Δ![P=p*g*y'](https://tex.z-dn.net/?f=P%3Dp%2Ag%2Ay%27)
Δ![P=1000kg/m^3*9.8m/s^2*40.0m=392x10^3Pa](https://tex.z-dn.net/?f=P%3D1000kg%2Fm%5E3%2A9.8m%2Fs%5E2%2A40.0m%3D392x10%5E3Pa)
![P=392kPa](https://tex.z-dn.net/?f=P%3D392kPa)
c.
It must be at the bottom since the pressure difference is greater than atmospheric pressure, so it wouldn't be able to lift the water all the way