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natita [175]
3 years ago
12

11. A 6.0‐m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 Hz, the wavelength is

0.40 m, and the amplitude is 4.0 mm, is propagating on the wire. The time for a crest of this wave to travel the length of the wire is closest to A) 19 ms B) 16 ms C) 21 ms D) 23 ms E) 25 ms
Physics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

Time will be 19 ms so option (a) is correct option

Explanation:

We have given that mass of wire m = 50 gram = 0.5 kg

Frequency f = 810 Hz

Wavelength = 0.4 m

Velocity is given by

v=wavelength\times frequency=810\times 0.4=324m/sec

Amplitude is given as d = 6 m

So time t=\frac{distance}{velocity}=\frac{6}{324}=0.01851=19ms

So option (a) is correct option

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makkiz [27]
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8 0
3 years ago
Read 2 more answers
You want to produce three 2.00-mm-diametercylindrical wires, each with a resistance of 1.00 Ω at room temperature. One wire is g
Vlada [557]

Answer:

(a) L =  128.75 m

(b) L =  182.56 m

(c) L =  114.28 m

(d) Mass of Gold = 7.68 kg = 7680 gram

(e) Cost of Gold Wire = $ 307040

Explanation:

The resistance of the wire is given as:

R = ρL/A

where,

R = Resistance

ρ = resistivity

L = Length

A = cross-sectional area

(a)

For Gold Wire:

ρ = 2.44 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (2.44 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(2.44 x 10⁻⁸ Ω.m)

<u>L =  128.75 m</u>

<u></u>

(b)

For Copper Wire:

ρ = 1.72 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (1.72 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(1.72 x 10⁻⁸ Ω.m)

<u>L =  182.56 m</u>

<u></u>

(c)

For Aluminum Wire:

ρ = 2.75 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (2.75 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(2.75 x 10⁻⁸ Ω.m)

<u>L =  114.28 m</u>

<u></u>

(d)

Density = Mass/Volume

Mass = (Density)(Volume)

Volume of Gold = AL = (3.14 x 10⁻⁶ m²)(128.75 m) = 4.04 x 10⁻⁴ m³

Therefore,

Mass of Gold = (1.9 x 10⁴ kg/m³)(4.04 x 10⁻⁴ m³)

<u>Mass of Gold = 7.68 kg = 7680 gram</u>

<u></u>

(e)

Cost of Gold Wire = (Unit Price of Gold)(Mass of Gold)

Cost of Gold Wire = ($ 40/gram)(7680 grams)

<u>Cost of Gold Wire = $ 307040</u>

7 0
3 years ago
(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.
Kitty [74]

The time taken for the tiny saliva to travel is 0.55 second.

The  horizontal distance traveled at speed of 4 m/s is 2.2 m.

The horizontal distance traveled at speed of 20 m/s is 11 m.

<h3>Time of motion of the tiny saliva</h3>

The time taken for the tiny saliva to travel is calculated as follows;

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity  = 0
  • g is the acceleration due to gravity

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

Substitute the given parameters and solve for time of motion;

t = √(2 x 1.5 / 10)

t = 0.55 second

<h3>Horizontal distance traveled at speed of 4 m/s</h3>

X = Vx(t)

X = (4 m/s)(0.55)

X = 2.2 m

<h3>Horizontal distance traveled at speed of 20 m/s</h3>

X = (20)(0.55)

X = 11 m

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

3 0
2 years ago
A scientific law is ____________________A. A rule enacted by the National Academy of Sciences. B. What scientists expect will al
lapo4ka [179]

Your question asks what a scientific law is.

Your answer would be B). What scientists expect will always happen under particular circumstances

A scientific law is something that will always happen, it is mostly like a repeat when doing a experiment with certain factors in place. This is also known as a "natural law" because something will naturally happen when it is enacted with the same factors for multiple "trials". This "scientific law" will allow scientist to predict what would happen during other multiple trials that are conducted. Concise data would be received from these trials.

An example of a scientific law is Newton's law of gravitation.

Therefore, your answer would be B.

5 0
3 years ago
two punds of water vapor at 30 psia fill the 4ft3 left chmaber of a partitioned system. The right chmaber has twice the volume o
tamaranim1 [39]

Answer:

pressure of water will be 49.7 atm

Explanation:

given data

pressure = 30 psi = 2.04 atm

water = 2 pound = 907.18

mole of water vapor = 907.19 /2 = 50.4 mole

volume = 4 ft³ = 113.2 L

temperature = 40 F = 277.59 K

to find out

pressure of water

solution

we will apply here ideal gas condition

that is

PV = nRT  .......................1

put here all value and here R = 0.0821 , T temperature and V volume and P pressure and n is no of mole

and we get here temperature

PV = nRT  

2.04 × 113.2 = 50.4×0.0821×T

solve it and we get

T = 55.8 K

so we have given right chamber has twice the volume of the left chamber i.e

volume = twice of volume + volume

volume = 2(113.2) + 113.2

volume = 339.6 L

so from equation 1 pressure will be

PV = nRT

P(339.6) = 50.4 × ( 0.0821) × (277.59)

P = 3.3822 atm = 49.7 atm

so pressure of water will be 49.7 atm

7 0
3 years ago
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