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Lapatulllka [165]
3 years ago
15

What happens when a population exceeds its carrying capacity?

Physics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

If a population exceeds carrying capacity, the ecosystem may become unsuitable for the species to survive. If the population exceeds the carrying capacity for a long period of time, resources may be completely depleted.

Mademuasel [1]3 years ago
4 0
They either die from not enough food, they move to another place, or sometimes they adapt to the amount of organisms there. That is all I know
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Which percentage best describes the visibility of a waxing crescent moon
Rus_ich [418]

Answer:

It be 0,1% - 49.9%

This is because the new moon is 0.0% and the first quarter is 50%.

3 0
2 years ago
How do mass and speed affect kinetic energy?
Lunna [17]
The mass affects the kinetic energy because the more the mass the more energy is given to the object and the speed<span> affects by making it go faster and longer, so whenever speed goes up so does energy.</span>
6 0
3 years ago
Read 2 more answers
If you run at an average speed of 10mi/h how long will it take for you to run 2.5miles
givi [52]

Answer:

If the avg speed is 10mi/h and you want to know how long it will take to run 2.5mi/h you put that as a ratio 2.5/10 which is 1/4 of an hour so it will take 15 minutes to run 2.5 miles

Explanation:

3 0
2 years ago
A tall, cylindrical chimney falls over when its base is ruptured. Treat the chimney as a thin rod of length 53.2 m. At the insta
rusak2 [61]
From an energy balance, we can use this formula to solve for the angular speed of the chimney

ω^2 = 3g / h sin θ

Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s

The formula for radial acceleration is:
a = rω^2

So,
a = 53.2 (0.987) = 52.494 /s^2

The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887

The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2

If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67° 
7 0
3 years ago
While strolling downtown on a Saturday afternoon, you stumble across an old car show. As you are walking along an alley toward a
snow_tiger [21]

Answer:

1.44 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a

This velocity will be the initial velocity of the car when it passes through the first building

s=ut+\frac{1}{2}at^2\\\Rightarrow 3=5a\times 0.4+\frac{1}{2}\times a\times 0.4^2\\\Rightarrow a=1.44\ m/s^2

The acceleration of the car is 1.44 m/s²

7 0
3 years ago
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