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harina [27]
3 years ago
14

Which of these phrases would go in the overlap? Check all that apply.

Physics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

1 & 5

Explanation:

Sati [7]3 years ago
5 0

Answer:

1. Found in the nucleus

5. Has mass of one amu

Explanation:

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3. What is the relationship among wave speed, wavelength, and frequency?
Rus_ich [418]

Answer:

Wave speed is related to both wavelength and wave frequency. Wavelength is the distance between two corresponding points on adjacent waves. Wave frequency is the number of waves that pass a fixed point in a given amount of time. This equation shows how the three factors are related:

Speed = Wavelength x Wave Frequency

Explanation:

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2 years ago
Development occurs:
Alex73 [517]

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D

Explanation:

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4 0
2 years ago
A hop is a springing from one foot but landing on the other foot? Question 4 options: True False
Rama09 [41]

Answer:

i thinc it's False

Explanation:

sorry im 6

6 0
3 years ago
Read 2 more answers
A swimming pool, 10.0 m by 4.0 m, is filled with water to a depth of 3.0 m at a temperature of 20.2°c. if the energy needed to r
Tomtit [17]

You need to find the mass of water in the pool.
Find the volume (10 x 4 x 3) = 120 m3

Water has a density of 1000g/m3,so 120 m3 = 120 x 1000 = 120 000 kg

[delta]H = 4.187 x 120 000 x 3.4 (and the units will be kJ)

You then use the heat of combustion knowing that each mole of methane releases 891 kJ of heat so if you divide 891 into the previous answer, you will get the number of moles of CH4


8 0
3 years ago
Read 2 more answers
An object is 39 cm away from a concave mirrors surface along the principles axis. If the mirrors focal length is 9.50 cm, how fa
Tatiana [17]

Answer:

12.6 cm

Explanation:

We can use the mirror equation to find the distance of the image from the mirror:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where here we have

f = 9.50 cm is the focal length

p = 39 cm is the distance of the object from the mirror

Solving the equation for q, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{9.50 cm}-\frac{1}{39 cm}=0.080 cm^{-1}\\q = \frac{1}{0.080 cm}=12.6 cm

5 0
3 years ago
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