A train reaches a speed of 35.0 m/s after accelerating at a rate of 5.00 m/s2 over a distance of 40.0 m. What was the train’s in
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Answer:
The magnitude of actual velocity is <u>496.67 mph</u> and its direction is <u>51.54° with the x axis in the third quadrant</u>.
Explanation:
Given:
Speed of jumbo jet in southwesterly direction = 550 mph
Velocity of jet stream from west to east direction
First let us draw a vectorial representation of the above velocity vectors.
Consider the south direction as negative y axis and west direction as negative x axis.
From the diagram,
The velocity of the jet can be represented as:
Similarly, the velocity of the stream is,
Now, the vector sum of the above two vectors gives the actual velocity of the aircraft. So, the resultant velocity is given as:
Now, magnitude is given as the square root of sum of the squares of the 'i' and 'j' components. So,
As the horizontal and vertical components of actual velocity negative, the resultant vector makes an angle with the x axis in the third quadrant.
The direction is given as:
Therefore, the magnitude of actual velocity is 496.67 mph and its direction is 51.54° with the x axis in the third quadrant.
