Answer:
2,3 -Dimethyl pentane
Explanation:
The given molecule is 2,3-Dimethyl pentane.
First of all select the longest chain of C-C atom. This will be the parent name.
In given structure the longest chain is straight chain that contain five carbon. Thus the parent name will pentane and there is no double or triple bond the given structure is of alkane.
Than locate the positions of functional groups attached.
In given structure there are two methyl groups are present. Give the name in such a way that functional groups will have lowest number. In given case we will start from the left.
The first methyl group will have number 2 and second will have number 3.
The name will be,
2,3-Dimethyl pentane
Answer:
The order of reaction is 2.
Rate constant is 0.0328 (M s)⁻¹
Explanation:
The rate of a reaction is inversely proportional to the time taken for the reaction.
As we are decreasing the concentration of the reactant the half life is increasing.
a) For zero order reaction: the half life is directly proportional to initial concentration of reactant
b) for first order reaction: the half life is independent of the initial concentration.
c) higher order reaction: The relation between half life and rate of reaction is:
Rate = ![\frac{1}{k[A_{0}]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%7D)
Half life =![K\frac{1}{[A_{0}]^{(n-1)} }](https://tex.z-dn.net/?f=K%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%20%7D)
![\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }](https://tex.z-dn.net/?f=%5Cfrac%7B%28halflife_%7B1%7D%29%7D%7B%28halflife_%7B2%7D%29%7D%3D%5Cfrac%7B%5BA_%7B2%7D%5D%5E%7B%28n-1%29%7D%7D%7B%5BA_%7B1%7D%5D%5E%7B%28n-1%29%7D%20%7D)
where n = order of reaction
Putting values
![\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B109%7D%7B231%7D%3D%5Cfrac%7B%5B0.132%5D%5E%7B%28n-1%29%7D%7D%7B%5B0.280%5D%5E%7B%28n-1%29%7D%7D)
Hence n = 2
![halflife=\frac{1}{k[A_{0}]}](https://tex.z-dn.net/?f=halflife%3D%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%7D)
Putting values
K = 0.0328
30.6 g of AgNO₃
Explanation:
We have the following chemical reaction:
Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃
Now we calculate the number of moles of Na₃PO₄:
number of moles = mass / molecular weight
number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles
Now we formulate the following reasoning:
if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃
then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃
X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃
mass = number of moles × molecular weight
mass of AgNO₃ = 0.18 × 170 = 30.6 g
Learn more about:
mole concept
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Given:
P = 123 kPa
V = 10.0 L
n = 0.500 moles
T = ?
Assume that the gas ideally, thus, we can use the ideal gas equation:
PV = nRT
where R = 0.0821 L atm/mol K
123 kPa * 1 atm/101.325 kPa * 10.0 L = 0.500 moles * 0.0821 Latm/molK * T
solve for T
T = 295.72 K<span />
