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MrRa [10]
3 years ago
15

Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s

Physics
1 answer:
Svetlanka [38]3 years ago
5 0
Using
KE = ½mv² = ½×1500×19×19 = 270750 joules
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If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:
GenaCL600 [577]
The frequency of the wheel is given by:
f= \frac{N}{t}
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3 years ago
Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a
cupoosta [38]

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

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