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S_A_V [24]
3 years ago
15

Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth

?
Physics
1 answer:
zimovet [89]3 years ago
6 0

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

   Work done = force x distance

  Weight is a force in the presence of gravity;

  Work done = weight x height of lifting

Height of lifting = \frac{work done }{weight}

 Height of lifting = \frac{250}{50} = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

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The International Space Station has a mass of 1.8 × 105 kg. A 70.0-kg astronaut inside the station pushes off one wall of the st
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a = 5.83 \times 10^{-4} m/s^2

Explanation:

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so here we know that

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now we know that

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now for the space station will be same as above force

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Graphs do not need to have a title.true or false
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A child (approximately 4 years old) takes her metal “slinky Toy” (a flexible coiled metal spring) and does various tests to dete
anzhelika [568]

Answer:

248

Explanation:

L = Inductance of the slinky = 130 μH = 130 x 10⁻⁶ H

l = length of the slinky = 3 m

N = number of turns in the slinky

r = radius of slinky = 4 cm = 0.04 m

Area of slinky is given as

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A = (3.14) (0.04)²

A = 0.005024 m²

Inductance is given as

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8 0
2 years ago
In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu
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Answer:

a)  Eₓ = - A y + 2B x , b)  Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

                    E = - dV / ds

a) Let's find the electric field on the x axis

                  Eₓ = - dV / dx

                  dV / dx = A y - B 2x

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b) calculate the electric field on the y-axis

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c) the electric field on the z axis

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.d) at which point the electric field is zero

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X axis

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We substitute this value in the previous equation

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             .y = 2 B C / A2

The correct answer is 3

6 0
3 years ago
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