5m
Explanation:
Given parameters:
Weight of object = 50N
Work done in lifting object = 250J
Unknown:
Vertical height = ?
Solution:
The work done on an object is the force applied to lift a body in a specific direction.
Work done = force x distance
Weight is a force in the presence of gravity;
Work done = weight x height of lifting
Height of lifting =
Height of lifting = = 5m
The vertical height through which the object was lifted is 5m
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Answer:
<em>W=700 Joule</em>
Explanation:
<u>Physics Work </u>
Is the dot product of the force vector by the displacement vector
When both the force and the displacements are pointed in the same direction, the formula reduces to its scalar version
The weightlifter is applying a net force of 350 N to lift the weights a distance of 2 m, thus the net work done is
Answer:
<u>velocity of swimmer relative to ground = 3 i -5 j</u>
Explanation:
Velocity of river = -5 j (south)
Velocity of swimmer relative to river = 3 i(north)
So
<h2>Velocity of swimmer relative to ground = Velocity of swimmer relative to river + Velocity of river</h2>Velocity of swimmer relative to ground = 3 i -5 j
So magnitude of total velocity is =
=
