Answer:
Chest experiences the friction forces towards right
Explanation:
Friction forces can be defined as a force a body experiences when it is made to slide against the surface. Friction force always acts to stop the the body which is moving. To stop the body, it always acts in the opposite directions to the motion of the body. Therefore, if the treasure chest is dragged across a sandy beach to the left, the frictional forces will act in the right direction.
To slow down or reduce speed.
V^2 = 700J/0.5*35kg
V = square root of 40
v = 6.324 m/s
Answer: 1.04N
Explanation:
Given
q1 = 2*10^-6C
q2 = 3.6*10^-6C
r = 0.25m
k = 9*10^9
Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."
F =(kq1q2) / r²
F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²
F = 0.0648/0.0625
F = 1.04N
The type of electrostatic force between the charges is the repulsive force
1.Landslide 2. Delta 3. Moving water 4. Erosion 5. Abrasion and Deflation
6. Winds 8. Sediment it can erode
Sorry, don't know 7.
