Answer:
T = 27.92 N
Explanation:
For this exercise let's use Newton's second law
T - W = m a
The weight
W = mg
The acceleration can be found by derivatives
a = dv / dt
v = 2 t + 0.6 t²
a = 2 + 0.6 t
We replace
T - mg = m (2 + 0.6t)
T = m (g + 2 + 0.6 t) (1)
Let's look for the time for the speed of 15 m / s
15 = 2 t + 0.6 t²
0.6 t² + 2 t - 15 = 0
We solve the second degree equation
t = [-2 ±√(4 - 4 0.6 (-15))] / 2 0.6
t = [-2 ±√40] / 1.3 = [-2 ± 6.325] / 1.2
We take the positive time
t = 3.6 s
Let's calculate from equation 1
T = 2.00 (9.8 + 2 + 0. 6 3.6)
T = 27.92 N
the equation of the line allows us to find the answer is
y = -27.8 t + 97.4
The equation of a line in a linear relationship between two variables, its general expression is
y = A x + B
in this case the slope is the quantity that the independent variable in this case A = -27.8 m / s
The cut-off point that is the value of the dependent variable for x = is b = 97.4 m
In this case we see that the slope has a unit of [m / s] and the dependent variable is a unit of length, therefore the independent variable must have a unit of time [s] so that the entire equation is in units of length
y = -27.8 t + 97.4
[m] = [m / s] [s] + [m]
[m] = [m]
The other two magnitudes with are necessary to write the equation r is the mean square root and gives an idea that the values also fit the line, the best value is 1
In conclusion, the equation of the line allows us to find the answer is
y = -27.8 t + 97.4
learn more about the equation inear here:
brainly.com/question/22851869
The answer would be Power
Answer: 0.077 M
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = 
t = time taken for decay process = 10 minutes
a = initial amount of the reactant= 0.859 M
a - x = amount left after decay process =?
Putting values in above equation, we get:
Thus the concentration of a after 10.0 minutes is 0.077 M.
Compared with an Earth year, a galactic year represents time on a grand scale but its not a consistent measurement across the galaxy
