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3 years ago

What must a mechanical wave travel through

1 answer:

5 0

A mechanical wave always consists of wiggles in some kind of material stuff. The material stuff may be air, water, rock, wood, steel ... almost anything, as long as it's some material. In general, whatever the waves are moving through is called the "medium". If there isn't any, like the vacuum in space, then mechanical waves can't travel there. For example, sound can't travel in space ... not even an inch.

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If the light rays in the incident ray originate at 20º from the surface...

Ainat [17]

Given :

The light rays in the incident ray originate at 20º from the surface.

To Find :

The angle for the incident ray.

Solution :

We know angle of incidence is measured from perpendicular to the surface .

So,

$\theta_i = 90^o - 20^o\\\\\theta_i = 70^o$

Now, we know by law of reflection :

Angle of reflection = Angle of incident

$\theta_r = 70^o$

Therefore, the angle of incident and reflection is 70° each.

5 0

3 years ago

A cannon fires a cannonball forward at a velocity of 48.1 m/s horizontally. If the cannon is on a mounted wagon 1.5 m tall, how

GalinKa [24]

Answer: 473.640 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the travel of the cannonball has two components: x-component and y-component. Being their main equations as follows:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=48.1 m/s$ is the cannonball's initial velocity

$\theta=0$ because we are told the cannonball is shot horizontally

$t$ is the time since the cannonball is shot until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=1.5m$ is the initial height of the cannonball

$y=0$ is the final height of the cannonball (when it finally hits the ground)

$g=9.8m/s^{2}$ is the acceleration due gravity

We need to find how far (horizontally) the cannonball has traveled before landing. This means we need to find the maximum distance in the x-component, let's call it $X_{max}$ and this occurs when $y=0$ .

So, firstly we will find the time with (2):

$0=1.5 m+48. 1 m/s sin(0\°) t-(4.9 m/s^{2})t^2$ (3)

Rearranging the equation:

$0=-(4.9 m/s^{2})t^2+48. 1 m/s sin(0\°) t+1.5 m$ (4)

$-(4.9 m/s^{2})t^2+(48. 1 m/s) t+1.5 m=0$ (5)

This is a <u>quadratic equation</u> (also called <u>equation of the second degree</u>) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (6)

Where:

$a=-4.9 m/s^{2}$

$b=48.1 m/s$

$c=1.5 m$

Substituting the known values:

$t=\frac{-48.1 \pm \sqrt{48.1^{2}-4(-4.9)(1.5)}}{2(-4.9)}$ (7)

Solving (7) we find the positive result is:

$t=9.847 s$ (8)

Substituting this value in (1):

$x=(48.1 m/s)cos(0\°) (9.847 s)$ (9)

$x=473.640 m$ This is the horizontal distance the cannonball traveled before it landed on the ground.

3 0

3 years ago

14. Which of the following accurately describes the differences between the SI and English systems of measurement?

nasty-shy [4]

Answer:

B. The English system is preferred for use in the scientific and technical communities due to its ease of us of the SI system

Explanation:

This is true due to the the fact that in the English system, all you have to do to change from one measurement to the other is just move the decimal place. For example: I have 10 kg of apples and wish to convert it into grams, kilo means 1000 and grams are the base, meaning one, so we will move the decimal place to the right three places (to add the three zeros for 1,000) and the answer will 10,000. Hope you read through this and somewhat get what I mean.

5 0

3 years ago

60 POINT!!!!!!

Genrish500 [490]

You in college stop cheating

8 0

3 years ago

Read 2 more answers

True or False: In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction (e

Delvig [45]

Answer:

false