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4 years ago

Describe how a change in resistance would affect the current in a circuit

1 answer:

Elena-2011 [213]4 years ago

8 0

Resistance typically opposes flow of current.

When the Resistance is increased, the current would be reduced, but when the Resistance is reduced, the current would be increased in the circuit.

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Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 2.33 m away from a waterfall 0.488 m in heigh

Ulleksa [173]

Answer:

5.68 m/s

Explanation:

The motion of the salmon is the same as a projectile: it is launched with an initial speed $u$ at an angle of $\theta=38^{\circ}$ above the horizontal.

The motion of the salmon consists of two indipendent motion:

- Along the horizontal direction, it is a uniform motion with constant velocity

$v_x = u cos \theta$

So that the distance travelled is

$d=v_x t = u cos \theta t$ (1)

- Along the vertical direction, it is a uniformly accelerated motion with constant acceleration downward, so the vertical displacement is

$y = u sin \theta t - \frac{1}{2}gt^2$ (2)

where g is the acceleration of gravity.

We know the following:

- The horizontal distance travelled by the salmon to reach the waterfall is

d = 2.33 m

- The vertical distance travelled is the height of the waterfall,

y = 0.488 m

From (1) we get:

$t=\frac{d}{u cos \theta}$

And substituting into (2), we can solve the equation to find t, the time at which the salmon reaches the waterfall:

$y = u sin \theta \frac{d}{u cos \theta} - \frac{1}{2}gt^2 = d tan \theta - \frac{1}{2}gt^2\\t = \sqrt{\frac{2(d tan \theta - y)}{g}}=\sqrt{\frac{2(2.33 tan 38^{\circ}-0.488)}{9.81}}=0.521 s$

And then, we can use eq.(1) again to find the initial speed, u:

$u=\frac{d}{cos \theta t}=\frac{2.33}{cos(38^{\circ})(0.521)}=5.68 m/s$

5 0

3 years ago

At a pressure 43 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of t

Allisa [31]

P = 43 * 10^3
V = 12 L

P' =?
V' = 8 L

PV = P'V'
43*10^3* 12 = P' * 8

I know you can do it from here, mate ;)

7 0

3 years ago

A 400 g ball swings in a vertical circle at the end of

solmaris [256]

Answer:

a = 25 m/s2

Explanation:

A = f/m

A = Speed/Acceleration

F =‘Force

M = Mass

3 0

3 years ago

Water flows into a swimming pool at the rate of 5.85 gal/min. If the pool dimensions are 21.2 ft wide, 46.1 ft long and 19.4 ft

Lana71 [14]

First, calculate volume:

volume = 21.2 ft * 46.1 ft * 19.4 ft

volume = 18,960 ft^3

Convert to gallon:

volume = 18,960 ft^3 * (12 in / 1 ft)^3 * (1 gallon / 231 in^3)

volume = 141,830.71 gallon

Therefore the time is:

time = 141,830.71 gallon / (5.85 gal/min)

time = 24,244.57 min

6 0

3 years ago

Pelden pushes a box of mass 30 kg with a force of 60 N. What is the

Firlakuza [10]

Answer:

Mass = 30kg

Force = 60N

Acceleration = ?

F = m/a

a = m/f

a = 30kg/ 60N

0.5ms^2 Answer

7 0

3 years ago