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3 years ago

In 2.8 s, a car increases its velocity from 20. M/s to 25 m/s. What is the acceleration of the car

Physics

1 answer:

Akimi4 [234]3 years ago

6 0

Acceleration= change in velocity/time; 5/2.8 , so a=1.785714286

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What are the effects of noise?

slega [8]

Answer:

Noise making has led to loss on hearing.

Explanation:

Supposing you like engaging in parties because of the noise of the sound system it can cause loss on hearing if continued for long

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3 years ago

Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?

noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

$k = 9 * 10^9$

$q_1 = 2pC$

$q_2 = 4pC$

$r = 6cm = 0.06 m$

now by using the above equation we have

$F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}$

$F = 2 * 10^{-11} N$

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

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3 years ago

Assume that a lightning bolt can be modeled as a long, straight line of current. If 16 C of charge passes by a point in 1.50 x 1

Reptile [31]

Answer:

$B = 7.9012*10^{-5}T$

Explanation:

To solve the problem, the concepts related to the magnetic field and the current produced in a lightning bolt are necessary.

The current is defined by the load due to time, that is to say

$I= \frac{q}{t}$

Where,

$q= Charge$

$t = time$

So the current can be expressed as:

$I = \frac{16}{1.5*10^{-3}}$

$I = 10666.67A$

Once the current is found it is now possible to find the magnetic field, as this is given by the equation,

$B =\frac{\mu_0}{2\pi}\frac{I}{r}$

Where,

$\mu_0 =$ Permeability Constant

I= Current

r= radius

Replacing the values we have

$B=\frac{4\pi*10^{-7}}{2\pi}(\frac{10666.67}{27})$

$B = 7.9012*10^{-5}T$

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3 years ago

The hottest climates on Earth are located near the Equator because this region

Ber [7]

You should select Choice-4 .

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3 years ago

There are stars located in the center bulge of the Milky Way and the spiral arms of the Milky Way. What is the difference betwee

nadya68 [22]

Answer:

The stars at the center bulge are bigger and brighter than the stars in the arms.

Explanation:

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3 years ago