Answer:
![A'=2A](https://tex.z-dn.net/?f=A%27%3D2A)
Explanation:
According to the law of conservation of energy, the total energy of the system can be expresed as the sum of the potential energy and kinetic energy:
![E=U+K=\frac{kA^2}{2}\\E=\frac{kx^2}{2}+\frac{mv^2}{2}=\frac{kA^2}{2}](https://tex.z-dn.net/?f=E%3DU%2BK%3D%5Cfrac%7BkA%5E2%7D%7B2%7D%5C%5CE%3D%5Cfrac%7Bkx%5E2%7D%7B2%7D%2B%5Cfrac%7Bmv%5E2%7D%7B2%7D%3D%5Cfrac%7BkA%5E2%7D%7B2%7D)
When the spring is in its equilibrium position, that is
, the object speed its maximum. So, we have:
![\frac{k(0)^2}{2}+\frac{mv_{max}^2}{2}=\frac{kA^2}{2}\\A^2=\frac{mv_{max}^2}{k}\\A=\sqrt{\frac{mv_{max}^2}{k}}](https://tex.z-dn.net/?f=%5Cfrac%7Bk%280%29%5E2%7D%7B2%7D%2B%5Cfrac%7Bmv_%7Bmax%7D%5E2%7D%7B2%7D%3D%5Cfrac%7BkA%5E2%7D%7B2%7D%5C%5CA%5E2%3D%5Cfrac%7Bmv_%7Bmax%7D%5E2%7D%7Bk%7D%5C%5CA%3D%5Csqrt%7B%5Cfrac%7Bmv_%7Bmax%7D%5E2%7D%7Bk%7D%7D)
In order to double its maximum speed, that is
. We have:
![A'=\sqrt{\frac{m(v'_{max})^2}{k}}\\A'=\sqrt{\frac{m(2v_{max})^2}{k}}\\A'=\sqrt{\frac{4mv_{max}^2}{k}}\\A'=2\sqrt{\frac{mv_{max}^2}{k}}\\A'=2A](https://tex.z-dn.net/?f=A%27%3D%5Csqrt%7B%5Cfrac%7Bm%28v%27_%7Bmax%7D%29%5E2%7D%7Bk%7D%7D%5C%5CA%27%3D%5Csqrt%7B%5Cfrac%7Bm%282v_%7Bmax%7D%29%5E2%7D%7Bk%7D%7D%5C%5CA%27%3D%5Csqrt%7B%5Cfrac%7B4mv_%7Bmax%7D%5E2%7D%7Bk%7D%7D%5C%5CA%27%3D2%5Csqrt%7B%5Cfrac%7Bmv_%7Bmax%7D%5E2%7D%7Bk%7D%7D%5C%5CA%27%3D2A)
Answer:
chemical energy
Explanation:
A form of energy is stored in the bonds between atoms is known as chemical energy.
velocity = traveled distance ÷ time of the traveled distance is seconds
velocity = 600 ÷ 60
velocity = 10 m/s
_________________________________
Kinetic Energy = 1/2 × mass × ( velocity )^2
KE = 1/2 × 60 × ( 10 )^2
KE = 30 × 100
KE = 3000 j
Answer:
(a) 4.0334Ω
(b)parallel
Explanation:
for resistors connected in parallel;
![\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR_%7Beq%7D%20%7D%20%3D%5Cfrac%7B1%7D%7BR1%7D%2B%5Cfrac%7B1%7D%7BR2%7D)
Req =3.03Ω , R1 =12.18Ω
![\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3.03%20%7D%20%3D%5Cfrac%7B1%7D%7B12.18%7D%2B%5Cfrac%7B1%7D%7BR2%7D)
![\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR2%7D%3D%5Cfrac%7B1%7D%7B3.03%20%7D-%5Cfrac%7B1%7D%7B12.18%7D)
![\frac{1}{R2}=0.2479](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR2%7D%3D0.2479)
R2=1/0.2479
R2=4.0334Ω
(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.
Req = R1+R2