Answer:
Area = 634.21 square metre
Step-by-step explanation:
Area of shaded region = Area of the circle - Area of the sector
Answer questions (a-d) for the following three data sets.
1 answer:
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Answer:
and
Step-by-step explanation:
An algebraic expression is a polynomial if and only if the variables involve have positive integral indices or exponents.
The given polynomial is:
We want to put one of the following polynomials in the blank space to create a fully simplified polynomial written in standard form.
A fully simplified polynomial written in standard form is obtained by writing the simplified polynomial in decreasing order according to degree.
Since the first term of having a degree of 5 and the last term is having a degree of 3.
The polynomial that goes into the blank must have a degree of 4.
This eliminates ,
and
We are now left with and
The required polynomial is therefore or
These two polynomials are in standard form and cannot be simplified further.
The correct choices are;
and
I think instead of "conjunction" it should say "conjecture"
Anyways, draw out a quadrilateral (see figure 1 attached). It can be any figure with 4 sides. Label the angles as A, B, C and D. The conjecture to prove is that A+B+C+D = 360. In other words, the sum of the four angles of any quadrilateral is always 360 degrees.
Draw a segment from A to C. This segment will cut the quadrilateral into two triangles. Re-label angle A to angle E and F. Do the same for angle C (label it G and H). Essentially, angle A = E+F and angle C = G+H.
See figure 2. Notice how I've color-coded things. The blue angles correspond to one triangle while the red angles correspond to the other triangle.
Since we know that three angles of a triangle always add to 180, we can say
B+G+E = 180
F+D+H = 180
Add the two equations (add left side separately; do the same for the right side)
Doing so leads to
B+G+E+F+D+H = 180+180
(E+F) + B + (G+H) + D = 360
A+B+C+D = 360
Which proves the conjecture
Anyways, draw out a quadrilateral (see figure 1 attached). It can be any figure with 4 sides. Label the angles as A, B, C and D. The conjecture to prove is that A+B+C+D = 360. In other words, the sum of the four angles of any quadrilateral is always 360 degrees.
Draw a segment from A to C. This segment will cut the quadrilateral into two triangles. Re-label angle A to angle E and F. Do the same for angle C (label it G and H). Essentially, angle A = E+F and angle C = G+H.
See figure 2. Notice how I've color-coded things. The blue angles correspond to one triangle while the red angles correspond to the other triangle.
Since we know that three angles of a triangle always add to 180, we can say
B+G+E = 180
F+D+H = 180
Add the two equations (add left side separately; do the same for the right side)
Doing so leads to
B+G+E+F+D+H = 180+180
(E+F) + B + (G+H) + D = 360
A+B+C+D = 360
Which proves the conjecture