The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:
<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Another quadrilateral that you might see is called a rhombus. All four sides of a rhombus are congruent. Its properties include that each pair of opposite sides is parallel, also making it a parallelogram. In summary, all squares are rectangles, but not all rectangles are squares.
Answer:
sin(A+B)=sinAcosB+cosAsinB. Putting the values in. sin(A+B)=(4/5)(−3/5)+(3/5)(−4/5). sin(A+B)=−24/25.
so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant
once you get "y", get any other trigonometry value you need :)
Answer:
f(x) = + cosx or - cosx
Step-by-step explanation:
(2+tan^2x/sec^2x) -1 =(f(x))^2
=(( 1 + sec^2x)/sec^2x) -1
= 1 / sec^2x + 1 - 1
= 1 / sec^2x
= cos^2x
(f(x))^2 = cos^2x
f(x) = + cosx or - cosx
