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Bezzdna [24]
3 years ago
15

Could you give me 4 examples of acceleration??

Physics
1 answer:
dangina [55]3 years ago
5 0
Certainly.

1). A driver presses the gas and the car speeds up.

2). A driver presses the brake and the car slows down.

3). A driver turns the steering wheel slightly. The car's speed doesn't change
as it goes around the curve.

4). A stone is tossed into the air. Gravity accelerates it from the moment it
leaves the thrower's hand until it hits the ground.

5). A new TV satellite is successfully launched and placed in a perfect circular
orbit around the Earth. The satellite's motion is accelerated forever, 24/7/365 .

"Acceleration" means any change in the speed or direction of motion.  Any
object that's not moving at constant speed in a straight line is accelerated.
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A 438 gram ball is traveling east at 39 m/s when it is hit by a 2.4 kg softball bat. After being in contact with the bat for 302
leonid [27]

Answer:

The magnitude of the impulse vector of the bat is 29.346 kg.m/s

The direction of the impulse vector of the bat is in the initial direction of the ball before impact

Explanation:

The given parameters are;

The mass of the ball, m₁ = 438 g

The speed of the ball = 39 m/s

The mass of the softball bat = 2.4 kg

The time of contact = 302 ms = 0.302 seconds

The speed of rebound = 28 m/s

The impulse = The change in momentum = Δp = F × Δt = m × Δv

The impulse on the ball = m₁ × Δv = 0.438 × (39 - (-28)) = 29.346 kg·m/s

Given that force of reaction of the bat is in opposite direction but equal to the force of the ball, and the time and the duration of contact with the ball is the same for both the ball and the bat, the impulse vector ore equal and opposite

Therefore, the magnitude of the impulse vector of the bat = 29.346 kg.m/s

The direction of the impulse vector of the bat = The initial direction of the ball before impact.

7 0
3 years ago
What kind of variation is there in the mechanical energy as the cart rolls down the ramp? Does this agree with your prediction?
Harlamova29_29 [7]

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         W_{nc} = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

6 0
3 years ago
By how many degrees fahrenheit can the temperature of one metric ton of water be raised with the addition of 110 thousand btus o
Svetllana [295]
1 BTU mean 1 degree of F increased for 1 pound mass. Since the mass unit is in kg that means you need to convert it into pound. One metric ton means 1000kg and 1 kg mean 2.20462lb, then the water mass is: 1000kg x 2.20462lb/kg= 2204.62lb.

You are putting 110,000 btus of heat, so the calculation would be

Temperature increase= energy/mass = 110000btus/ 2204.62lb= 49.9 degree
5 0
4 years ago
What does the second law of thermodynamics say about entropy apex?
sesenic [268]

The entropy of the universe is increasing


8 0
3 years ago
Read 2 more answers
a football player starts from rest and speeds up to a final velocity of 12 m/s. the speeding up takes a total of 6 seconds. what
gizmo_the_mogwai [7]

Answer:

2 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 6 s

Acceleration (a) =?

The acceleration of the player can be obtained as follow:

v = u + at

12 = 0 + (a × 6)

12 = 6a

Divide both side by 6

a = 12 / 6

a = 2 m/s²

Thus, the acceleration of the player is 2 m/s²

8 0
3 years ago
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