Answer:
Explanation:
Given that,
Mass of the object, m = 29 kg
Torsion constant of the wire, K = 1.14 N-m
Number of cycles, n = 98
Time, t = 74 s
To find,
The rotational inertia of the object.
Solution,
Relationship between the moment of inertia, time period and the torsion constant of the spring is given by :
Where I is the moment of inertia
K is spring constant
Let T Is the time period of oscillation, such that,
So, the rotational inertia of the object is .
Here’s my work to your question. If you need clarification feel free to drop something in the comment section.
Answer:
2.40 x 10⁻¹³ C
Explanation:
= number of electrons = 6.25 x 10⁶
= charge on electron = - 1.6 x 10⁻¹⁹ C
= number of protons = 7.75 x 10⁶
= charge on proton = 1.6 x 10⁻¹⁹ C
Net charge is given as
Q = +
Q = (- 1.6 x 10⁻¹⁹) (6.25 x 10⁶) + (1.6 x 10⁻¹⁹) (7.75 x 10⁶)
Q = 2.40 x 10⁻¹³ C
Answer:
120 kg m/s
Explanation:
The magnitude of the momentum of an object is given by
where
m is the mass of the object
v is its speed
For the block in this problem,
m = 10.0 kg (mass of the block)
v = 12.0 m/s (speed of the block)
Therefore the magnitude of the block's momentum is
Answer:
so to find the acceleration we divide the change in velocity by the time taken for it so intial velocity was 3m/s and final velocity is 10m/s. we substract 3 from 10 to get the change in velocity ie 10m/s -3m/s = 7m/s. now decide this by the time taken for it that is 4 sec as given. acceleration is 7/4 = 1.75m/s^2