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vova2212 [387]
2 years ago
8

An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull

ey is L = 2.0 m. When the oscillator is set to a frequency of 150 Hz, a standing wave with six loops is formed. What must be the linear mass density of the cord?
Physics
1 answer:
puteri [66]2 years ago
6 0

Answer:

\mu=0.0049Kg/m

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

f_n=\frac{nv}{2L}

Where L is the length of the string and v the velocity of propagation. Use this expression to find the value of v.

f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s

The velocity of propagation is given by the expression:

v=\sqrt{\frac{T}{\mu }

Where \mu is the desirable variable of the problem, the linear mass density, and T is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

T=W=mg=(5)(9.81)=49.05N

With the value of the tension and the velocity you can find the mass density:

v=\sqrt{\frac{T}{\mu}

v^2=\frac{T}{\mu}\\ \mu=\frac{T}{v^2} =\frac{49.05}{(100)^2} =\frac{49.05}{10000} =0.0049Kg/m

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Basile [38]

1) Mechanical energy is conserved in all the 4 situations

2) True

3) The potential energy of the block is 490 J

Explanation:

1)

Mechanical energy is the sum of potential energy (PE) and kinetic energy (KE) of a body:

E=PE+KE

According to the law of conservation of energy, in absence of non-conservative forces (such as air resistance, friction...), the mechanical energy of a body is always conserved.

This means that the mechanical energy is conserved in all the situations described. More specifically:

- Child on a swing : there is a continuous conversion between kinetic energy and gravitational potential energy

- Pendulum : there is a continuous conversion between kinetic energy and gravitational potential energy

Bow and Arrow : there is a conversion of energy from elastic potential (when the bow is stretched) to kinetic energy (when the arrow is shot)

Roller Coaster: there is a continuous conversion between kinetic energy and gravitational potential energy

2)

As we  said, the mechanical energy of the object falling down at any point of the fall is

E=KE+PE

where KE is the kinetic energy and PE is the potential energy. The value of E is constant, since the mechanical energy is conserved.

The potential energy is given by

PE=mgh

where m is the mass of the object, g is the acceleration of gravity, h is the height of the object above the ground.

As the object falls, its height h decreases, and therefore, the potential energy PE also decreases. But we said that E must remain constant: therefore, if PE decreases, this means that KE increases, therefore as the object falls, the potential energy is converted into kinetic energy (in fact, the  speed of the object increases). So the statement is true.

3)

The potential energy of an object is given by the equation

PE=mgh

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object relative to the ground

For the block in this problem, we have:

m = 10 kg

h = 5 m

Substituting, we find its potential energy:

PE=(10)(9.8)(5)=490 J

Learn more about potential energy and kinetic energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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