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4 years ago

Which factor is most important in determining climate?

Physics

1 answer:

valentina_108 [34]4 years ago

5 0

I think Is b the first question

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A car veers off course and runs straight into a brick wall. This is an example

ValentinkaMS [17]

Short time large force

4 0

3 years ago

A region of space in which a test charge experiences a force is referred to as

Alecsey [184]

Answer: The correct answer is- Field.

Explanation -

The modified space around a charged particle is known as electric field.

The strength of electric field at a point is calculated as the force experienced by a unit test charge present at that point.

Thus, a region of space in which a test charge experiences a force is referred to as Field.

4 0

3 years ago

Read 2 more answers

The ____ is a line drawn at a right angle to a barrier. a. normal c. node b. ray d. wave front

Natalija [7]

Answer:

a. normal

Explanation:

In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.

5 0

3 years ago

When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st

defon

Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

Power drawn by hairdryer is P = 1650 watt

We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So $1650=110\times I$

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0

4 years ago

A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.

iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2$

Converting to m/s²

$a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

$\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g$

Hence, acceleration of the car is -0.64525g

8 0

4 years ago