Answer:
The speed of the heavier fragment is 0.335c.
Explanation:
Given that,
Mass of the lighter fragment 
Mass of the heavier fragment 
Speed of lighter fragment = 0.893c
We need to calculate the speed of the heavier fragment
Let v is the speed of the second fragment after decay
Using conservation of relativistic momentum













Hence, The speed of the heavier fragment is 0.335c.
Answer:
300 miles per hour
Explanation:
Speed is distance per unit time, expressed as s=d/t where t is the time taken, d is distance covered and s is the speed.
Convering s to hrs
To convert seconds to hours, we knkw that 1 hour has 60 minutes and each minute has 60 seconds. Therefore, 1 hour has 60*60=3600 seconds
If 3600s=1 h
60 s=?
By cross multiplication 60s*1 h/3600s=1/60 hours
Given distance as 5 miles and time as 1/60 hours then the speed will be 5 divided by 1/60 hrs which is equivalent to 5*60=300 miles per hour
t = 0.527 s
<u>It accelerates for 0.527 s.</u>
<u>Explanation:</u>
We use the formula:
v = u+at
Given:
v = 106 m/s
u = 0 (since no gravity)

So applying the formula,
v = u+at
106 = 0 + 201t
t = 106/201
t = 0.527 s
Answer: <em>4</em><em>2</em><em>.</em><em>3</em><em>2</em><em> </em><em>ms-1</em>
Explanation:
v = u+ at
v = 24.4 + ( 3.2×5.6)
v = 42.32 ms-1
Answer
for every meters it will go up 15 so if it was 2 secoonds it woudl be 30 and if it was 3 seconds it would be 45 meters
Explanation: