What is potential energy called that is associated with objects that can be stretched

What is the power of a juice machine that draws 0.18 amps of current and has a resistance of 75 ohms

densk [106]

Answer:
Option B

Explanation:

7 0

2 years ago

A cyclist maintains a constant velocity of 4.1 m/s headed away from point A. At some initial time, the cyclist is 244 m from poi

astra-53 [7]

Answer:

$d=490\ m$ is his final displacement from the point A after 60 seconds.

Explanation:

Given:

Cyclist is moving away from A.

velocity of cyclist, $v=4.1\ m.s^{-1}$

displacement of the cyclist from point A at the time of observation, $d_i=244\ m$

time after which the next observation is to be recorded, $t=60\ s$

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

$\Delta d=v.t$

$\Delta d = 4.1 \times 60$

$\Delta d=246\ m$

<u>Now the the final displacement from point A after the mentioned time:</u>

$d=d_i+\Delta d$

$d=244+246$

$d=490\ m$

6 0

3 years ago

A hand pump is being used to inflate a bicycle tire that has a gauge pressure of 41.0 lb/in2. If the pump is a cylinder of lengt

damaskus [11]

Answer:

L - h = 12.3672 in

Explanation:

Given

P = 41.0 lb/in² = 41 P.S.I

L = 16.8 in

A = 3.00 in²

h = ?

In order that air flows into the tire, the pressure in the pump must be more than the tire pressure, 41.0 PSI.

We assume that air follows ideal gas equation, the temperature of the compressed air remains constant as the piston moves down. Taking one atmospheric pressure to be 14.6959 P.S.I , we can use the ideal gas equation

P*V = n*R*T

As number of moles of air do not change during its compression in the pump, n*R*T of the gas equation is constant. Therefore we have

P₁*V₁ = P₂*V₂ ⇒ V₂ = P₁*V₁ / P₂

where

1 and 2 are initial and final states respectively,

V₁ = A*L = (3.00 in²)*(16.8 in) ⇒ V₁ = 50.4 in³

P₁ = 14.6959 P.S.I

P₂ = P₁ + P = (14.6959 lb/in²) + (41.0 lb/in²) = 55.6959 lb/in²

Inserting various values we get

V₂ = (14.6959 P.S.I)*(50.4 in³) / (55.6959 lb/in²)

⇒ V₂ = 13.2985 in³

Length of pump, measured from bottom, this volume corresponds to is

h = V₂ / A = (13.2985 in³) / (3.00 in²)

⇒ h = 4.4328 in

Piston must be pushed down by more than

L - h = 16.8 in - 4.4328 in = 12.3672 in

4 0

3 years ago

HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!

Julli [10]

Hello! Sorry this is a little late!

The answer to your question would best be option C, y<span>es, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

I just took this test, and can 100% confirm this is the correct answer!

Hope this helps, and have a great day! :)</span>

8 0

3 years ago

Read 2 more answers

After a long night of cramming for a test, your college room-mate hits his head forcefully against the wall of your room in desp

zhannawk [14.2K]

Answer: the wall contracts the force exerted by his head. The wall produces the opposite force which is equal to the force his head bangs the wall with.

Explanation: if his head exerts a much greater force than the wall can counteract the wall will be destroyed, if the wall exerts a much greater force than his head exerts he will be pushed far back and might even suffer a broken head.

The wall in this case provides the opposite reactive force.

6 0

3 years ago