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olya-2409 [2.1K]
3 years ago
10

What is potential energy called that is associated with objects that can be stretched

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0
Elastic potential energy
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A cell phone uses a 3. 0 V battery. The circuit board it uses needs a 0. 05 A current. What size resistor is needed to generate
Marta_Voda [28]

The value of resistance will be 60 ohms. Resistance is the opposition force offered to the flow of electric current. The ratio of the voltage to the electric current passing through the wire.

<h3>What is a resistor?</h3>

A resistor is a two-terminal passive electrical component that acts as a circuit element by implementing electrical resistance.

Resistors are used to limit current flow, alter signal levels, divide voltages, bias active devices, and complete transmission lines in electronic circuits.

The given data in the problem is;

V is the voltage =  3. 0 V

I is value of electric current=  0. 05 A

R is the resistance=?

According to ohm's law, the potential difference between the two ends of the conductor is equal to the product of electric current and the resistance generated.

So from the ohm law;

V= IR

\rm R = \frac{V}{I} \\\\ \rm R = \frac{3}{0.05} \\\\ \rm R =60 \ ohm

Hence the value of resistance will be 60 ohms.

To learn more about the resistor refer to the link;

brainly.com/question/1322424

3 0
2 years ago
A pizza parlor is considering adding taco pizza and Hawaiian pizza to its
tia_tia [17]

Answer: 79

Explanation:

7 0
3 years ago
Read 2 more answers
Unlike a mixture, pure substance has_____
irinina [24]
A pure substance contain only a single type of molecule 

7 0
3 years ago
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(II) A 0.450-kg hockey puck, moving east with a speed of 5.80 m/s, has a head-on collision with a 0.900-kg puck initially at res
Alisiya [41]

Answer:

The second puck moves with a speed of 3.867 m/s due east and the first puck moves with a speed of 1.933 m/s, but in the Western direction after collision.

Explanation:

Let the mass of the first hockey puck = m₁ = 0.45 kg

Mass of the resting puck = m₂ = 0.90 kg

Velocity of the first hockey puck = v₁ = 5.80î m/s; magnitude = 5.80 m/s

Velocity of resting puck = v₂ = 0 m/s

Mass of the two pucks are the same after collision.

Velocity of first puck after collision = v₃ = ?

Velocity of second puck after collision = v₄ = ?

In an elastic collision, both momentum and kinetic energy are conserved.

Momentum before collision = momentum after collision

Momentum before collision

m₁v₁ + m₂v₂ = (0.45 × 5.8) + (0.9 × 0) = 2.61 kgm/s

Momentum after collision

m₁v₃ + m₂v₄ = 0.45v₃ + 0.9v₄

So, according to the law of conservation of Momentum,

2.61 = 0.45v₃ + 0.9v₄ (eqn 1)

Kinetic energy before collision = kinetic energy after collision

Kinetic energy before collision = (m₁v₁²/2) + (m₂v₂²/2) = (0.45 × 5.8²/2) + (0.9 × 0²/2) = 7.569 J

Kinetic energy after collision = (m₁v₃²/2) + (m₂v₄²/2) = (0.45v₃²/2) + (0.9v₄²/2) = 0.225v₃² + 0.45v₄²

Since kinetic energy is conserved,

7.569 = 0.225v₃² + 0.45v₄² (eqn 2)

2.61 = 0.45v₃ + 0.9v₄ (eqn 1)

7.569 = 0.225v₃² + 0.45v₄² (eqn 2)

Make v₃ the subject of formula from eqn 1,

v₃ = (2.61 - 0.9v₄)/0.45 = (5.8 - 2v₄)

Substitute the value of v₃ into eqn 2

7.569 = 0.225(5.8 - 2v₄)² + 0.45v₄²

7.569 = 0.225(33.64 - 23.2v₄ + 4v₄²) + 0.45v₄²

7.569 = 7.569 - 5.22v₄ + 0.9v₄² + 0.45v₄²

1.35v₄² - 5.22v₄ = 0

v₄² - 3.867v₄ = 0

v₄ (v₄ - 3.867) = 0

v₄ = 0 m/s or v₄ = 3.867 m/s

If v₄ = 0 m/s,

v₃ = (5.8 - 2v₄) = [5.8 - 2(0)] = 5.8 m/s

If v₄ = 3.867 m/s

v₃ = (5.8 - 2v₄) = [5.8 - 2(3.867)] = - 1.933 m/s

The (v₃,v₄) answers are (5.8,0) and (-1.933,3.867). Since the collision was stated to be elastic, the realistic answer is the (-1.933, 3.867) answer.

So, the answer is interpreted as,

The second puck moves with a speed of 3.867 m/s due east and the first puck moves with a speed of 1.933 m/s, but in the Western direction after collision.

4 0
3 years ago
In the wheel and axel system below 12 lbs. Of effort is used to turn the axel, which provided 70 lbs. Of resistance. If the diam
netineya [11]

Answer:

2.57in

Explanation:

Let's assume the efficiency of the wheel and axle system is 100%

Efficiency = MA/VR ×100

100 = MA/VR × 100

MA/VR = 1

mechanical Advantage MA = Load/effort

MA = 70/12

MA = 5.83

Velocity ratio VR = Diameter of wheel/diameter of axle

VR = 15/d

Substitute into the formula the given data and get d

1 = (70/12)÷(15/d)

1 = 70/12×d/15

1 = 70d/180

Cross multiply

180 = 70d

d = 180/70

d = 18/7

d = 2.57in

Hence the maximum diameter of the axle is 2.57in

6 0
3 years ago
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