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expeople1 [14]
3 years ago
11

HELP IM IN A EXAM!!!

Physics
2 answers:
natali 33 [55]3 years ago
8 0
Answer:

Species A and C

Explanation: none
Vesna [10]3 years ago
7 0

Answer:

answer is b and c

Explanation:

i got it right

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Why is the power of concave lense negative​
Travka [436]

Answer:

because the focal length is negative.

Explanation:

Power of a lens (P) is the reciprocal of its focal length (f).

4 0
3 years ago
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling w
3241004551 [841]

Solution :

c). $\vec{F}_A = $ force applied by Abe

   $\vec{F}_B = $ force applied by Barry

   $\vec{F}_E = $ force applied by Eric

   $\vec{F}_R = $ Resultant force

$\vec{F}_A $  in the vector form can be written as :

         $\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B $  in the vector form can be written as :

         $\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B $

     $=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

    $=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

   $ = \tan ^{-1}\left(\frac{60}{60}\right)$

  = 45°  north east

The direction of the force E is  45° west or  45° south west.

   

8 0
3 years ago
Two objects (38.0 and 17.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
fgiga [73]

Answer:

a) 3.7 m/s^2

b) 231.8 N

Explanation:

Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2

a)

F1 = m1g and F2 = m2g

So Fnet = F1 + F2

Since the pulleys will move in different directions when accelerating...

Fnet = F1 - F2

M×a = m1g - mg2

M×a = g×(m1 -m2)

a = g×(m1 - m2)/M

a = 9.8×(38 - 17)/(38 + 17)

a = 3.7 m/s^2

b)

Looking at the part for m2

Fnet  = T - m2g

-m2×a = T - m2g

T = m2(g - a)

T = 231.8 N

7 0
3 years ago
This is from P.E , que some please help me
bonufazy [111]

Answer:

I know that 2 is called a foul I dont know about 1 though

3 0
3 years ago
A cyclist is travelling at 4 metres per second for 100 metres,<br> how long does it take?
Slav-nsk [51]

Answer:

25 seconds!

Explanation:

I just had to find what number to multiply 4 to get 100 and it was 25

4x25=100

Or you could do the easier way by dividing 100 by 4 which has the same answer: 25

100÷4=25

7 0
4 years ago
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