The distance of separation between the lenses is determined as 12 cm.
<h3>
Distance of image formed by the first lens</h3>
The distance of the image formed by the first lens is calculated as follows;
1/d₁ = 1/f - 1/di₀
1/di₁ = 1/4 - 1/12
1/di₁ = 2/12
1/di₁ = 1/6
di₁ = 6 cm
<h3>Find the final position of the image</h3>
Use magnification formula as shown below;
M = (di₁di₂)/(d₀₁d₀₂)
1 = (di₁di₂)/(d₀₁d₀₂)
di₂ = (d₀₁d₀₂)/(di₁)
di₂ = (12 x d₀₂)/(6)
di₂ = 2d₀₂
1/f = 1/ d₀₂ + 1/di₂
1/f = 1/ d₀₂ + 1/2d₀₂
1/f = 1.5/d₀₂
d₀₂ = 1.5f
d₀₂ = 1.5(4 cm) = 6 cm
<h3>Distance between the two converging lens</h3>
D = di₁ + d₀₂
D = 6 cm + 6 cm
D = 12 cm
Thus, the distance of separation between the lenses is determined as 12 cm.
Learn more about distance between lens here: brainly.com/question/12993552
#SPJ1
a=363.593m/s*2 we have rectangular component of force so we first find force resultant by square both component then square root and finally divide with 0.2 kg mass
Answer: The two answers are the machine will require an input greater than 100 ft.-lbs. And the other is The machine may accomplish the task faster than manual work.
Hope this help :3
Answer:
29.6 kg
Explanation:
Centripetal force = mass × centripetal acceleration
F = m v² / r
88.0 N = m (2.50 m/s)² / 2.10 m
m = 29.6 kg
