Ask question

Ask question

All categories

2 years ago

11

Define: primary and secondary coils

1 answer:

Hoochie [10]2 years ago

6 0

<em><u>Primary coil:</u></em><em><u /></em><u />
It is the part of electric circuit in which input voltage is applied,,and it induces current in neighbouring secondary coil...
<em><u>Secondary coil:</u></em><em><u /></em><u />
It is the coil in which current is induced by primary coil...

You might be interested in

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$

Now the force of friction is $F_s=\mu*N,$ where $N$ is the normal force and from the diagram it is $F_y=mg*cos(\theta).$

Thus $F_s=\mu*N=\mu*mg*cos(\theta).$

Therefore,

$F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).$

Substituting the value for $F_H,m,\mu, and \:\theta$ we get:

$F_{tot}= -38.63N.$

Now acceleration is simply

$a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.$

The negative sign indicates that the acceleration is directed up the incline.

Part B:

$d=\frac{1}{2} at^2$

Which can be rearranged to solve for t:

$t=\sqrt{\frac{2d}{a} }$

Substitute the value of $d=0.50m$ and $a=7.7m/s$ and we get:

$t=0.36s.$

which is our answer.

Notice that in using the formula to calculate time we used the positive value of $a$ , because for this formula absolute value is needed.

5 0

3 years ago

What is the force acting on a 10kg object that accelerates from 5 m/s to 20 m/s in 5s?

vitfil [10]

Answer:

Option C

Explanation:

v= u + at

20 = 5 + a(5)

15= a(5)

a= 3 m/s²

Force = mass × acceleration

= 10 × 3

= 30 N

3 0

2 years ago

An organism is made up of

lilavasa [31]

B.) A group of cells working together. If it were D.), the question would have had to be A cell is made up of...

8 0

3 years ago

stiv31 [10]

Answer:

The answer is Letter B The car travel at a constant veloc

5 0

2 years ago

A beetle crawling around on a desk walks 19 cm in 17 seconds to the right. It then changes direction and walks 6 cm in 6 seconds

Andre45 [30]

Answer: 11.5secs

Explanation:

They said what the average speed is so to find the average you have to find the mean so 17secs + 6secs = 23secs / 2 = 11.5secs.

6 0

3 years ago