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alexira [117]
3 years ago
7

What is in the blank?

Physics
1 answer:
Vika [28.1K]3 years ago
8 0
This is in the thermosphere which is at an altitude of 85-520km
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What is a positive effect of increased carbon dioxide within the carbon cycle?
MaRussiya [10]

Answer:

The positive impact in the cycle is that CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.

Explanation:

Carbon cycle is the process by which carbon dioxide travels from the atmosphere to the earth and returns back to the atmosphere.

The negative impact of carbon dioxide in the carbon cycle is that it will cause green house effect. However, when it comes to the positive impact in the cycle, CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.

5 0
3 years ago
What is your height in centimeters? what is your weight in Newton's
goldfiish [28.3K]
My height is 178 centimeters.
My weight is 700N.
4 0
3 years ago
Read 2 more answers
A high voltage transmission line with a resistance of 0.51 Ω/km carries a current of 1099 A. The line is at a potential of 1300
Illusion [34]
<h2>Answer:</h2>

\boxed{P=96.09MW}

<h2>Explanation:</h2>

First of all, we need to figure out what is the resistance in that line. In this problem, the total resistance is not given directly, but we can calculate it because we know it in terms of 0.51 Ω/km and since the distance from the power station to the city is 156km, then:

R_{line}=0.51 \frac{\Omega}{km}.156km \\ \\ R_{line}=79.56\Omega

So we can calculate the power loss as:

P=I^2R \\ \\ Where: \\ \\I=1099A \\ \\ P=(1099)^2(79.56) \\ \\ P=96092647.56W \\ \\ Remember \ that \ 1MW=10^6W \ So: \\ \\ P=96092647.56W(\frac{1M}{10^6}) \\ \\ \boxed{P=96.09MW}

Finally, the power loss due to resistance in the line is 96.09MW

5 0
3 years ago
How is a magnetic field generated?
alekssr [168]
It would be B I think
4 0
3 years ago
A 100 W incandescent lightbulb emits about 5 W of visible light. (The other 95 W are emitted as infrared radiation or lost as he
frutty [35]

Answer:

n = 1.89 x 10¹⁹ photons/s

Explanation:

given,

Power of bulb = 100 W

Visible light = 5 W

wavelength of the visible light = 600 nm

number of photons emitted per second

using formula of wavelength

\lambda = \dfrac{c}{\nu}

\nu= \dfrac{c}{\lambda}

\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}

\nu=5 \times 10^{14}\ Hz

energy of photon

U = h υ

U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴

U = 2.65 x 10⁻¹⁹ J

number of photon

n = \dfrac{P}{U}

n = \dfrac{5}{2.65 \times 10^{-19}}

n = 1.89 x 10¹⁹ photons/s

6 0
3 years ago
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