Question

If A and B are mutually exclusive events, with P(A) = 0.19 and P(B) = 0.27, what is P(A or B)?

Answer 1

Answer: 0.46

Step-by-step explanation:

We know that when two events X and Y are mutually exclusive, then

$\text{P(X or Y)}=P(X)+P(Y),\ \ \ \text{Since }P(X\cap Y)=0$

Given:  A and B are mutually exclusive events, with

P(A) = 0.19 and P(B) = 0.2

Now, $\text{P(A or B)=P(A)+P(B)}\\\\\Rightarrow\text{P( A or B)}=0.19+0.27\\\\\Rightarrow\text{P( A or B)}=0.46$

Answer 2

I believe it's 0.46
hope it helped