All categories

3 years ago

What’s the compound name for V2(S2O3)3

Chemistry

1 answer:

ohaa [14]3 years ago

7 0

Answer: I HOPE THIS HELPS, HAVE A GREAT EARLY HALLOWEEN

Explanation:

PubChem CID: 1084

Molecular Formula: S2O3(2−) or O3S2-2

Synonyms: Thiosulphate THIOSULFATE ION sulfurothioate UNII-LLT6XV39PY Thiosulfate (S2O32-) More...

Molecular Weight: 112.13 g/mol

You might be interested in

Baby Mice

alexgriva [62]

Answer:

I would say for #1 Fiona and for #2 sexual

Explanation:

Please give brailiest

6 0

3 years ago

What is the term for an irregular way a mineral breaks apart?

kari74 [83]

Answer:

That would be fracture

Explanation:

A way that a mineral breaks apart curved at the edges or split into uneven pieces

6 0

3 years ago

Why do electrons enter the 4s orbital before entering the 3d orbital?

salantis [7]

Answer:

C. because the 4s orbital is at a lower energy level

7 0

3 years ago

Read 2 more answers

What is the purpose of attaching the clip/ clamp with graphite of the the pencil to the battery?

Sonja [21]

The pencil attached to the negative terminal of the battery collects hydrogen gas while the one connected to the positive terminal collects oxygen.

4 0

3 years ago

Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo

Romashka-Z-Leto [24]

Answer:

$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

Explanation:

Volume of a cone:

$\displaystyle V=\frac{1}{3} \pi r^2 h$

We have $\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}$ and we want to find $\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?$ when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

$\displaystyle V =\frac{1}{3} \pi (5h)^2 h$
$\displaystyle V =\frac{1}{3} \pi \ 25h^3$

Differentiate this equation with respect to time t.

$\displaystyle \frac{dV}{dt} =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}$
$\displaystyle \frac{dV}{dt} =25 \pi h^2 \ \frac{dh}{dt}$

Plug known values into the equation and solve for dh/dt.

$\displaystyle 10 = 25 \pi (2)^2 \ \frac{dh}{dt}$
$\displaystyle 10 = 100 \pi \ \frac{dh}{dt}$

Divide both sides by 100π to solve for dh/dt.

$\displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}$
$\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}$

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0

3 years ago