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Natasha2012 [34]
3 years ago
14

Why do trains use steel wheels rather than rubber tires?                                                                 A) Stee

l wheels provide more grip, making it easier to stop a train.
B) Rubber tires don't provide enough friction to allow the train to move.
C) Steel wheels increase friction, thus making it easier to move the load.
D) Steel wheels reduce friction, thus requiring less force to move the load.
Physics
2 answers:
Andrej [43]3 years ago
5 0
Steel wheels reduce friction, thus requiring less force to move the load.
kotegsom [21]3 years ago
4 0
D) steel wheels reduce friction, thus requiring less force to move the load.  Friction between rubber and steel would be greater than steel and steel.  Friction creates heat, which represents a loss of energy (which has to come from somewhere else - likely from the kinetic energy of the train)
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The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×10^
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I had the same quiz… it’s a
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All stars, regardless of size, eventually _____.
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They all eventually burn out or explode. 
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Divers change their body position in midair while rotating about their center of mass. In one dive, the diver leaves the board w
OlgaM077 [116]

Answer:

Her angular velocity when tucked is greater than when straight by a factor of 0.23

Explanation:

Moment of inertia (I) = mr^2 = mv^2/w^2

m is mass of the diver

v is diver's linear velocity

w is her angular velocity

When straight, I = 14 kg.m^2

mv^2/w^2 = 14

w^2 = mv^2/14

w = sqrt(mv^2/14) = 0.27sqrt(mv^2)

When tucked, I = 4 kg.m^2

w^2 = mv^2/4

w = sqrt(mv^2/4) = 0.5sqrt(mv^2)

Her angular velocity when tucked is greater than when straight by 0.23 (0.5 - 0.27 = 0.23)

5 0
4 years ago
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The overall energy involved in the formation of CsCl from Cs(s) and Cl2(g) is −443 kJ/mol. Given the following information: heat
german

Answer :  The magnitude of the lattice energy for CsCl is, 667 KJ/mole

Explanation :

The steps involved in the born-Haber cycle for the formation of CsCl :

(1) Conversion of solid calcium into gaseous cesium atoms.

Cs(s)\overset{\Delta H_s}\rightarrow Cs(g)

\Delta H_s = sublimation energy of calcium

(2) Conversion of gaseous cesium atoms into gaseous cesium ions.

Ca(g)\overset{\Delta H_I}\rightarrow Ca^{+1}(g)

\Delta H_I = ionization energy of calcium

(3) Conversion of molecular gaseous chlorine into gaseous chlorine atoms.

Cl_2(g)\overset{\frac{1}{2}\Delta H_D}\rightarrow Cl(g)

\Delta H_D = dissociation energy of chlorine

(4) Conversion of gaseous chlorine atoms into gaseous chlorine ions.

Cl(g)\overset{\Delta H_E}\rightarrow Cl^-(g)

\Delta H_E = electron affinity energy of chlorine

(5) Conversion of gaseous cations and gaseous anion into solid cesium chloride.

Cs^{1+}(g)+Cl^-(g)\overset{\Delta H_L}\rightarrow CsCl(s)

\Delta H_L = lattice energy of calcium chloride

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I+\Delta H_D+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

-443KJ/mole=76KJ/mole+376KJ/mole+121KJ/mole+(-349KJ/mole)+\Delta H_L

\Delta H_L=-667KJ/mole

The negative sign indicates that for exothermic reaction, the lattice energy will be negative.

Therefore, the magnitude of the lattice energy for CsCl is, 667 KJ/mole

5 0
4 years ago
EOLOOO
steposvetlana [31]

Answer:

λ = 2 m

f = 100 Hz

Explanation:

When struck in the middle an anti-node is formed at the center, So you can derive,

f = \frac{1}{2l} \sqrt{\frac{T}{m} }

f = frequency of the fundamental mode in producing standing waves

l = resonating length

T = tension of the wire

m = linear density of the wire

(check the attachment)

By substituting,

f = \frac{1}{2×1} \sqrt{\frac{4×10}{10⁻³} }

f = 100 Hz

Wavelength is twice the vibrating  length, its in the section standing waves and using that only the equation is derived.

Imagine what happens when two identical waves in opposite direction superimpose. There will be 3 nodes and two anti-nodes where the distance between two nodes is half the wavelength.

The same case happen here, the transverse sound wave traveling along the wire get reflected by a bridge and bounce back on itself where superposition takes place. So two nodes are at the bridges hence the twice of the distance between bridges is the wavelength of the sound wave.

Download pdf
8 0
3 years ago
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