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Natasha2012 [34]
3 years ago
14

Why do trains use steel wheels rather than rubber tires?                                                                 A) Stee

l wheels provide more grip, making it easier to stop a train.
B) Rubber tires don't provide enough friction to allow the train to move.
C) Steel wheels increase friction, thus making it easier to move the load.
D) Steel wheels reduce friction, thus requiring less force to move the load.
Physics
2 answers:
Andrej [43]3 years ago
5 0
Steel wheels reduce friction, thus requiring less force to move the load.
kotegsom [21]3 years ago
4 0
D) steel wheels reduce friction, thus requiring less force to move the load.  Friction between rubber and steel would be greater than steel and steel.  Friction creates heat, which represents a loss of energy (which has to come from somewhere else - likely from the kinetic energy of the train)
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Which method can be used for separating a mixture of sand and salt?
Veronika [31]
Answers A and C can be automatically eliminated because evaporation has to do with the water cycle and magnetism has to do with electric current and such. Next we can eliminate B or distillation because it also has to do with water/liquids. Therefore, the answer is D or filtration because it is the only answer left.

I hope this helps!
6 0
3 years ago
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When reaching a boundary between two media (1 and 2), an incident ray is partially reflected and partially refracted. The ray is
lukranit [14]

Answer:

The angle of incidence when the reflected ray is perpendicular to the incident ray = 45°

Explanation:

According to Snell's Law,

n₁ sin θ₁ = n₂ sin θ₂

When the angle between the incident ray and reflected ray is 90°, the angle of incidence is θ₁ and the angle of reflection, θ₂ = 90° - θ₁ and the index of refraction in the Snell's Law for both media would be the same, n₁ = n₂ = n

n sin θ₁ = n sin (90° - θ₁)

Note that from trigonometric relations,

Sin (90° - θ₁) = cos θ₁

n sin θ₁ = n cos θ₁

(sin θ₁)/(cos θ₁) = 1

tan θ₁ = 1

θ₁ = arctan 1 = 45°

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7 0
3 years ago
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2 years ago
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suppose you increase your walking speed from 4 m/s to 12 m/s in a period of 1 second what is your acceleration
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a   = 12 ms⁻¹ - 4ms⁻¹ / 1 s

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7 0
3 years ago
Calculate the aceleration of a vehicle wich start with a zero meter per second, and acelerates to 34 m/s in 21 s.
Leviafan [203]

Answer:

For the aceleration we have:

Vf = Vo + a * t

Clearing "a":

a = (Vf - Vo) / t

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a = 34 m/s / 21 s

a = 1,61 m/s^2

The aceleration of the vehicle is<u> 1,61 meters per second squared</u>

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