Question

Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq) + CH3CO2H(aq) --> CH3CO2–(aq) + H2O(l) + CO2(g)(B) HCO3–(aq) + H+(aq) --> H2CO3(aq) (C) HCO3–(aq) + H+(aq) --> H2O(l) + CO2(g)(D) NaHCO3(aq) + H+(aq) --> H2CO3(s) + Na+(aq)2(E) NaHCO3(aq) + CH3CO2H(aq) --> 2 Na2CO3(aq) + CH4(aq) + 2H2O(l) + CO2(g)

Answer 1

Answer: The correct answer is Option C.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:

$NaHCO_3(aq.)+CH_3COOH(aq.)\rightarrow CH_3COONa(aq.)+H_2O(l)+CO_2(g)$

Ionic form of the above equation follows:

$Na^+(aq.)+HCO_3^-(aq.)+CH_3COO^-(aq.)+H^+(aq.)\rightarrow CH_3COO^-(aq.)+Na^+(aq.)+H_2O(l)+CO_2(g)$

As, sodium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$HCO_3^-(aq.)+H^+(aq.)\rightarrow CO_2(g)+H_2O(l)$

Hence, the correct answer is Option C.