<span>50.2 kJ = 333 kJ/kg * mass of water
mass of water is 0.15075075075075075075075075075075 kg
therefore mass of unfrozen water is 0.10924924924924924924924924924925 kg</span>
Answer:
The answer to your question is V2 = 4.97 l
Explanation:
Data
Volume 1 = V1 = 4.40 L Volume 2 =
Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C
Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg
Process
1.- Convert temperature to °K
T1 = 19 + 273 = 292°K
T2 = 37 + 273 = 310°K
2.- Use the combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (783 x 4.40 x 310) / (292 x 735)
-Simplification
V2 = 1068012 / 214620
-Result
V2 = 4.97 l
Note that
1 m = 3.2808 ft
Therefore
1 km = 3280.8 ft
and
Answer: 1.0682 x 10⁵ ft/hr
Answer:
C
Explanation:
If you move the decimal to the left it transforms the expression into scientific notation.
Answer:
the value of H° is below -6535 kj. +6H2O
Explanation:
6H2O answer solved
