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Butoxors [25]
1 year ago
12

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or

neutral:NaHS;
Chemistry
1 answer:
Julli [10]1 year ago
7 0

NaHS is an acidic salt.

NaHS is obtained by replacement of one acidic hydrogen of `H2S` by Na (on reaction with NaOH).

<h3>What do we know about NaHS?</h3>

The chemical compound with the formula NaSH is sodium hydrosulfide. This substance is created when hydrogen sulfide is partially neutralized with sodium hydroxide. In the industrial setting, sodium sulfide and NaSH are frequently employed for the same things. Solid NaSH has no color.

Solution of sodium hydrosulfide is a colorless to light-yellow liquid. corrosive to flesh and metals. It is employed in the production of colors and paper pulp.

To learn more about acidic salt:

brainly.com/question/7178280

#SPJ4

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Answer:

In 33.7 grams SnF2 we have 8.17 grams of F

Explanation:

Step 1: Data given

Mass of SnF2 = 33.7 grams

Molar mass of SnF2 = 156.69 g/mol

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Step 2: Calculate moles of SnF2

Moles SnF2 = mass / molar mass

Moles SnF2 = 33.7 grams / 156.69 g/mol

Moles SnF2 = 0.215 moles

Step 3: Calculate moles F

For 1 mol SnF2 we have 2 moles F

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Step 4: Calculate mass F

Mass F = moles F * molar mass F

Mass F = 0.430 moles * 19.00 g/mol

Mass F = 8.17 grams

In 33.7 grams SnF2 we have 8.17 grams of F

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