I₂ (g) + Br₂ (g) ↔ 2IBr (g)
Given is Kc = 280 at 150 degree C.
Kc = [IBr]² / [I₂][Br₂]
Initially [IBr] = 0.45 / 2 = 0.225 M
The actual reaction is:
2IBr ↔ I₂ + Br₂, Kc = 1/280 = 0.00357142
In equilibrium,
[IBr] = 0.225 - 2x
[I₂] = x
[Br₂] = x
By substituting the values we get,
K = [I₂] [Br₂] / [IBr]²
0.00357142 = x×x / (0.225 - 2x)²
√(0.00357142) = x / (0.225 - 2x)
0.0597613 (0.225 - 2x) = x
0.01344 - 2 × 0.0597613x = x
(1 + 2 × 0.0597613)x = 0.01344
x = 0.01344 / (1+2 × 0.0597613)
x = 0.01344 / 1.1195226
x = 0.012005
Substituting the values we get,
IBr = 0.225 - 2 × 0.012005 = 0.17698 M
I₂ = x = 0.012005 M
Br₂ = 0.012005 M
Answer:
6 molecules of Oxygen
Explanation:
From the question ,
Sugar has a molecular formula of C₆H₁₂O₆ .
Hence ,
Using the mole concept , i.e. ,
1 molecule of Sugar , i.e. , C₆H₁₂O₆ has , 6 molecules of Carbon , 12 molecules of Hydrogen and 6 molecules of Oxygen .
Therefore ,
6 molecules of Oxygen is present in 1 molecule of sugar , i.e. , C₆H₁₂O₆ .
D.Perpendicular to both the magnetic field and the current direction
More molecules in the sawdust can collide with oxygen molecules
Answer:
The greater the energy required to break a bond, the stronger that bond must be.
Explanation:
Most iconic bonds are considerably stronger, more difficult to break, than covalent bonds.
Hope this helps! :) x
