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enot [183]
2 years ago
15

Which oxide is Mn2O3?

Chemistry
2 answers:
ziro4ka [17]2 years ago
8 0

Manganese Oxide?????

Irina18 [472]2 years ago
7 0

Manganese oxide is a blackish/ brown solid and the primary natural source of manganese. Oxide compounds are not conductive to electricity.

the answer is Manganese Oxide (Mn2O3)

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What object has 13 protons
bekas [8.4K]

Answer:

The isotope Al-27 has 13 protons

Explanation:

5 0
3 years ago
Number of H in 3(NH4)2Cro4
zlopas [31]

The number of H atoms in 3(NH₄)₂CrO₄ = 24

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

Subscripts in the chemical formula indicate the number of atoms

The compound of 3(NH₄)₂CrO₄ ( 3 molecules of (NH₄)₂CrO₄ ) :

Number of H :

\tt 4\times 2(subscript)\times 3(coefficient,number~of~molecules)=24~atoms

7 0
2 years ago
How many elements does the periodic table have quick my wifi not working help please
dlinn [17]
There is 118 elements<span> in the periodic table</span>
3 0
3 years ago
A cylinder with a moveable piston contains 0.552 mol of gas and has a volume of 259 mL . Part A What will its volume be if an ad
Naddik [55]

Answer:

The new volume will be 367mL

Explanation:

Using PV = nRT

V1 = 259mL = 0.000259L

n1 = 0.552moles

At constant temperature and pressure, the value is

P * 0.000259 = 0.552 * RT ------equation 1

= 0.552 / 0.000259

= 2131.274

V2 = ?

n2 = 0.552 + 0.232

n2 = 0.784mole

Using ideal gas equation,

PV = nRT

P * V2 = 0.784 * RT ---------- equation 2

Combining equations 1 and 2 we have;

V2 = 0.784 / 2131.274

V2 = 0.000367L

V2 = 367mL

7 0
3 years ago
A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

0.756= Total moles from the mixture

Moles of Ar + Moles of H₂ = 0.756 moles

Moles of Ar + 1.10 g / 2g/mol = 0.756 moles

Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206

We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g

8 0
2 years ago
Read 2 more answers
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