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Hatshy [7]
3 years ago
5

Explain why a solution that is 1.3 M HF and 1.3 mM KF is not a good buffer. HF is a strong acid and cannot be used in a buffer s

ystem. The ratio of acid to conjugate base is outside the buffer range of 10:1. The two species are not a conjugate acid base pair. KF is not soluble in water and cannot be used in a buffer system.
Chemistry
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

The ratio of acid to conjugate base is outside the buffer range of 10:1.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}

A buffer should have

\dfrac{1}{10} \leq \dfrac{\text{[A$^{-}]$}}{\text{[HA]}} \leq \dfrac{10}{1}

For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is

\dfrac{1.3 \times 10^{-3} }{1.3} = \dfrac{1}{1000}

The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.

A is wrong. NF is a weak acid.

C is wrong. The two species are a conjugate acid-base pair.

D is wrong. Salts of Group 1 metals are soluble.

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A) When the temperature inside the container increases, the pressure inside the container increases as well. 

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C) At a molecular level, when the temperature is raised the kinetic energy of the molecules inside the container will increase. This increase in the kinetic energy will cause the molecules to move faster, and to hit the walls of the container more often. This causes an increase in the pressure inside the container because there more hits means more force on the walls of the container, and that is the definition of pressure. 

Have a nice day!
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