Question

Two 4.3546 cm x 4.3546 cm square aluminum electrodes, spaced 0.6408 mm apart are connected to a 73.68 V battery. What is the capacitance in pico Farads?

Answer 1

Answer:

Capacitance, C = 26.1 picofarad

Explanation:

It is given that,

Side of square, x = 4.3546 cm = 0.043546 m

Distance between electrodes, d = 0.6408 mm = 0.0006408 m

Voltage, V = 73.68 V

Capacitance of parallel plates is given by :

$C=\dfrac{\epsilon_oA}{d}$

$C=\dfrac{8.85\times 10^{-12}\times (0.043546)^2}{0.0006408}$

$C=2.61\times 10^{-11}\ F$

or

C = 26.1 picofarad

So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.