Answer:
1,070.41 grams of DDT will be formed .Explanation:
1) 
Moles of chlorobenzene = 
According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :
of chloral
2) Moles of chloral = 
According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :
of chloro benzene
As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.
According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :
Mass of 3.0195 moles of DTT :
3.0195 mol × 354.5 g/mol = 1,070.41 g
1,070.41 grams of DDT will be formed .
What you have to do is balance the chemical equations to make sure everything is even on both sides. If you want me to help you answer the questions comment back
The senate only allows two senates from each state.
Answer:
Yes, Mass is conserved.
Explanation:
Every chemical reactions obey the law of conservation of mass. The law of conservation of mass states that in chemical reactions, mass is always constant.
Equation:
2Na + Cl₂ → 2NaCl
From the equation above, one can observe that the reaction started using 2 atoms of Na and it produced 2 atoms of the same element in NaCl. A molecule of Cl produced 2 atoms of Cl in the NaCl
Design a simple experiment to support your answer:
Aim: To demonstrate the law of conservation of mass
One Na atom weighs 23g
Two Na atom will weigh 2 x 23 = 46g
1 atom of Cl is 35.5g
1 molecule of Cl containing two atoms of Cl will weigh 2 x 35.5 = 71g
Total mass of reactants = mass of 2Na + 1Cl₂ = (46 + 71)g = 117g
On the product side, Mass of 1 NaCl = 23+ 35.5 = 58.5g
Two moles of NaCl will give 2 x 58.5g = 117g
Since the mass on both side is the same, one can say mass is conserved.
Answer:
The sp³ orbital hybridization has 25% s-character and 75% p-character.
Explanation:
Hybridization refers to the process of mixing of a given number atomic orbitals to form equal number of new hybrid orbitals. The three types of hybrid orbitals are sp³, sp² and sp.
The<u> four sp³ hybridized orbitals</u> are formed by the mixing of <u>one s orbital and three p orbitals.</u>
Thus s-character in a sp³ hybridized orbital = (1÷4)×100 = 25%
and p-character in a sp³ hybridized orbital = (3÷4)×100 = 75%
<u>Therefore, the sp³ orbital hybridization has 25% s-character and 75% p-character.</u>
