Answer:
The presence of 1-2% ethanol as catalyst, suppresses the oxidation of chloroform with oxygen to give a poisonous gas called phosgene. ... Here glycerol acts as negative catalyst. Criteria or characteristics of catalysts. i. The mass and chemical composition of catalyst should remain unchanged at the end of the reaction.
Explanation:
Hmm... interesting topic you're writing about here!
Well, for this essay, there must be specific criteria, correct? I'll make some suggestions, but of course you don't have to go by them if you don't like 'em. So... here they are!:
- List the physical and chemical properties of glue
- List the physical and chemical properties of liquid corn starch
- Compare and contrast the physical and chemical properties of glue with the physical and chemical properties of liquid corn starch
- You can conduct some experiments with the two substances also! You can mix the two together and see how they react with each other, and incorporate the results of the experiment into your essay.
- You can mix glue with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the glue mixes with creates a homogeneous or heterogeneous mixture, etc.
- You can mix liquid corn starch with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the liquid corn starch mixes with creates a homogeneous or heterogeneous mixture, etc.
That's all I can come up with at the moment. Maybe you'll take some of these suggestions into consideration...? Anyhow, I hope I helped somehow! :)
Answer:
3.10g
Explanation:
Please see the attached picture for the full solution.
Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is
To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
It’s definitely B but I’m not sure
