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3 years ago

The reed switch is placed between the poles of the strong permanent magnet.

Physics

1 answer:

Lina20 [59]3 years ago

5 0

Answer:

he switch is open when the magnetic field is activated, a magnetic force is applied to the reed, which causes it to move, closing the circuit and allowing the lock to open.

Explanation:

The reed switches, this is metallic, generally iron, in general the switch is open when the magnetic field is activated, a magnetic force is applied to the reed, which causes it to move, closing the circuit and allowing the lock to open.

The force is given by

F = i l x B

In the systems when the switch is depressed the magnetic field is created in a solenoid and this field attracts the metal of the reed.

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2 years ago

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3 years ago

If the only forces acting on a 2.0kg mass are F1 = (3i-8j)N and F2 = (5i+3j)N, what is the magnitude of the acceleration of the

belka [17]

Answer: 4.7m/s²

Explanation:

According to newton's first law,

Force = mass × acceleration

Since we are given more the one force, we will take the resultant of the two vectors.

Mass = 2.0kg

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Adding component wise, we have;

F1+F2 = 3i+5i-8j+3j

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Resultant of the sum of the forces will be;

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R² = 8²+5²

R² = 64+25

R² = 89

R = √89

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Our resultant force = 9.4N

Substituting in the formula

F = ma

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a = 9.4/2

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3 years ago

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