136 multiply 34x4 and it will equal 136
Which describes the combination of two primary colors of light to produce a secondary color of light?
a. Yellow light and blue light combine to produce green light.
b. Magenta light and cyan light combine to produce blue light.
c. Red light and green light combine to produce yellow light.
d. Green light and yellow light combine to produce white light.
Answer:
b. Magenta light and cyan light combine to produce blue light.
Explanation:
Primary colour is any of three colours which, when added to or subtracted from others in different amounts, can generate all other colours.
• Red, blue and green are additive primary colours..
• Magenta, yellow and cyan are subtractive primary colours.
Answer:
1.12 m
0.08291 m
Explanation:
u = Upstream velocity = 0.4 m/s
Re = Reynold's number = (turbulent)
= Viscosity of water =
Here the flow is turbulent so we have the relation
The approximate location downstream from the leading edge where the boundary layer becomes turbulent is 1.4 m
Boundary layer thickness relation is given by
The boundary layer thickness is 0.08291 m
Answer:
the exposed core of a dead star, supported by electron degeneracy pressure.
Explanation:
A white dwarf is a low luminosity exposed core of a dead star having mass comparable to the sun but volume comparable to the earth . So its density is very high . These stars have lost the capacity to generate energy through the process of fusion . Due to high gravitational energy , it goes on shrinking but ultimately balanced by electron degeneracy pressure. It is not a main sequence star as it has lost the power of fusion .
Answer:
See explanation below.
Explanation:
For this case we atart fom the proportional model given by the following differential equation:
And if we rewrite this expression we got:
If we integrate both sides we got:
And using exponential on both sides we got:
Where represent the initial amount for the isotope and t the time in years and A the amount remaining.
If we want to apply a model for the half life we know that after some time definfd the amount remaining is the hal, so if we apply this we got:
We can cancel and we got:
If we solve for k we can apply natural log on both sides and we got:
And that would be our proportional constant on this case.
If we replace this value for k int our model we will see that:
And using properties of logs we can rewrite this like that:
And thats the common formula used for the helf life time.