Answer:
KE_2 = 3.48J
Explanation:
Conservation of Energy
E_1 = E_2
PE_1+KE_1 = PE_2+KE_2
m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²
(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2
4.10J+0.914J = 1.53J + KE_2
5.01J = 1.53J + KE_2
KE_2 = 3.48J
Answer:
Physical changes are changes affecting the form of a chemical substance
Explanation:
<u> Answers</u>
1. precision
2. density
3. control
4. matter
5. accuracy
6. gradation
<u>Explanation</u>
1. An indication of how close a measurement is to the correct result is called precision.
2. The mass of a substance per unit volume is called density of a substance.
3. A quantity in an experiment that remains unchanged or constant is called a control group.
4. Anything that has mass and occupies space is called matter.
5. The degree to which a measurement can be replicated is called accuracy.
6. Scale markings that denote equal units of measure is called gradation.
