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madam [21]
3 years ago
11

a titration of 25.0mL of an x M hcl solution with 0.15M NaOH starts at a burette reading for NaOH of 0.20mL . Thr burette readin

g of the end point is 24.10mL. what is the volume of NaOH dispensed?
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
6 0
Burette is a very accurate measuring instrument when adding solutions and has a measurement error of 0.05 mL. 
Small volumes of solutions can be transferred from the burette at a controllable rate. 
In this instance NaOH is in the burette.
Initial reading of NaOH is 0.20 mL 
end point is the point at which the chemical reaction reaches completion. In acid base reactions, end point is when all the H⁺ ions have reacted with OH⁻ ions. 
final reading of NaOH is 24.10 mL
to find the volume of NaOH dispensed we have to find the difference between final reading and initial reading 
volume of NaOH added = 24.10 mL - 0.20 mL = 23.90 mL
volume of NaOH dispensed is 23.90 mL
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In finding the molarity of a solution, we use the following formula:

M=moles soluteL solution

What is Molarity?

The number of moles of the solute is calculated by dividing the mass of the solute by its molar mass.

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The molar mass of  NH4NO3 and (NH4)3PO4 are  80.043 g/mol and 149.0867 g/mol, respectively.

molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol

molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol

total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol

molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol

[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4

[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4

Therefore, [PO3−4]\\ has a molarity of  1.48×10−3 M PO3−

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2 years ago
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Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

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