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Jet001 [13]
3 years ago
5

According to the equation for this chemical reaction, what does the 2 in front of 2Ag tell us?

Chemistry
2 answers:
kotykmax [81]3 years ago
4 0

Answer:

It tell us that it's necessary 2 moles of Ag in the stoichiometric proportion of the reaction.

Explanation:

The equation of a chemical reaction is a representation of the ideal reaction: 100% yield of the products and without parallel reactions. So, the equation presents the stoichiometric quantities of the substance. For example, for a generic reaction:

A + 2B → 3C

It says that it's necessary 1 mol of A and 2 moles o B to form 3 moles of C. Thus, the numbers before the substances represents the stoichiometric number of moles of that substance.

storchak [24]3 years ago
3 0
The number of molecules involved in the reaction, in this case, the number of Ag atoms involved.
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The answer is B. The carrying capacity will decrease, forcing the population to decrease as well.
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Relation between glancing and angle of deviation<br>​
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Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0
2 years ago
For the reaction 2A(g) â B(g), the equilibrium constant is Kp = 0.76. A reaction mixture initially contains 4.0 atm of gas (PA =
timofeeve [1]

Answer: (a) The reaction mixture will proceed toward products.

Explanation:

Equilibrium constant is defined as the ratio of pressure of products to the pressure of reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

2A(g)\rightleftharpoons B(g)

The expression for Q_p is written as:

Q_p=\frac{p_B}{(p_A)^2}

Q_p=\frac{(2.0)}{(2.0)^2}

Q_p=0.5

K_p=0.76

Thus as K_p>Q_p , the reaction will shift towards the right i.e. towards the product side.

7 0
3 years ago
How many moles of salt are in 13.8 g of sodium chloride?
Hoochie [10]

Answer: 0.24 moles

Explanation:

Molecular Mass of NaCl (23 + 35.5) = 58.5g

58.5g of Sodium Chloride -------> 1 mole of NaCl

∴ 13.8g of Sodium Chloride  ------>  1 ÷58.5 x  13.8 = 0.2358974  ≈    0.24moles

                                                         -  

3 0
3 years ago
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The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
3 years ago
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