Answer:
Radius of curvature of the mirror = 250 cm
Explanation:
Given:
Object distance from mirror = 250 cm (u=-250)
Object distance appears in mirror = 250 cm (v=-250)
Find:
Radius of curvature of the mirror
Computation:
Using mirror formula
1/f = 1/v + 1/u
1/f = 1/(-250) + 1/(-250)
f = (-250/2)
f = -125 cm or 125 cm
Radius of curvature of the mirror = 2(f)
Radius of curvature of the mirror = 2(125)
Radius of curvature of the mirror = 250 cm
He said that the atom is mostly empty space with a positive nucleus in the center with electrons around it.
Answer:
(a) The electron will move towards the wire.
The direction of the magnetic fields created by the wire can be found via right-hand rule. If you point your thumb towards the direction of the current, and if you curl your fingers, the direction of your four fingers will give the direction of the magnetic field. In this case, magnetic field is around the wire, and into the page just above the wire, where the electron is located.

According to the above formula, the direction of the force the wire applies to the electron can be found by right-hand rule.
Since the electron has a negative charge, the direction of the force is towards the wire.
(b) The proton will veer to the right.
The direction of the magnetic field is the same as the previous part. The proton has a positive charge, and coming from above. The direction of its velocity is downwards. The magnetic field above the wire is pointed into the page. Using the right-hand rule, the magnetic force on the proton is directed to the right, with respect to us.
Answer:
∑ τ =0, L₀ = 
Explanation:
In a circular turning movement, when the arms are extended and then contracted in two possibilities:
- They are lowered the force of gravity is what pulls them, the tension of the muscle becomes zero to allow this movement.
In this movement the force is vertical(gravity) and the movement of the center of mass of each arm is vertical, so that the work is the weight value of the arm by the distance traveled by the center of mass.
- Another possibility is that the arms have stuck to the body, in this case the person's muscles perform the force, this force is horizontal and the displacement is the horizontal of the center of mass of the arms from the extended position to the contracted
In these movements the torque of the external force is equal for each arm, but in the opposite direction, so they are canceled where a net torque of zero, this causes the angular momentum to be preserved, which changes is the moment of inertia of the system and therefore you must also change the angular velocity to keep your product constant
∑ τ =0
L₀ = 
I₀ w₀ = I w
The answer is the Second one