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3 years ago

Before the widespread use of computers, how was the epicenter of an earthquake determined?

2 answers:

7 0

Data was used from three different stations. Where their data overlapped was where the epicenter was located.
it is called triangulation

STALIN [3.7K]3 years ago

7 0

Data was used from three different stations. Where their data overlapped was where the epicenter was located.

You might be interested in

The order in which atomic orbitals are filled is based on what factor?. . A- The potential energy of the orbital.. . B- The high

Gnoma [55]

The order in which atomic orbitals by electrons are filled is based on the Aufbau principle which states that orbitals are filled in increasing energy level. The answer that applies here is C. The overall energy level of the orbital.

8 0

3 years ago

Three equal charges of magnitude 'e' are located at the vertices of an equilateral triangle of side 1m. Where should you place a

Naily [24]

Answer:

At centroid

Explanation:

In the given equilateral triangle ABC with side of 1 m. The three equal charges e,e,e are placed at the A,B and C.

And the fourth charge 2e is put at point O which is called centroid.

Now we can calculate the distance AD by applying pythagorean theorem as,

$AD^{2}=AB^{2}+BD^{2}$

Put the values and get.

$AD^{2}=1^{2}+(\frac{1}{2} )^{2}\\AD=\sqrt{\frac{3}{4} } \\AD=\frac{\sqrt{3}}{2}$

Now calculate AO as,

$AO=\frac{2}{3}\times \frac{\sqrt{3} }{2}\\AO=\frac{1}{\sqrt{3} }$

And the sides BO=CO=AO.

Now Force can be calculated as

$F_{1}=\frac{2ke^{2} }{\frac{1}{\sqrt{3} } ^{2} }\\F_{1}=6ke^{2}$

And similarly,

$F_{2}=F_{3}=6ke^{2}$

Now we can calculate resultant of $F_{2}andF_{3}$ in upward direction. as,

$F_{net}=\sqrt{F_{2}^{2}+F_{3}^{2}+2F_{2}F_{3}cos120 } \\F_{net}=\sqrt{F_{2}^{2}+F_{2}^{2}+2F_{2}F_{2}(-\frac{1}{2})}\\F_{net}=6ke^{2}$

Therefore the resultant force on centroid O.

$F=F_{1}-F_{net}\\F=6ke^{2}-6ke^{2}\\F=0$

Therefore the fourth charge 2e should be placed on centroid so that it experience zero force.

8 0

3 years ago

A car is traveling at a velocity of 13.5 m/sec (30 mph) north on a straight road. The mass of the car is 1,000 kg. Calculate the

Nat2105 [25]

Answer:

<em> The momentum of the body would be 13500 kg .m/sec</em>

Explanation:

What Momentum Entails

momentum is a property that is possed by all moving objects, it is a product of mass and velocity. A moving object has a magnitude which is the mass of the body and direction which is the velocity towards a certain direction, so it is a vector quantity

Step by Step Calculation

The momentum of a body can be gotten from the expression below;

p = m x v

where p is the momentum

m is the mass of the body = 1000 kg

v is the velocity = 13.5 m/sec

Given these parameters our momentum would be;

p = 1000 kg x 13.5 m/sec

p = 13500 kg . m/sec

Therefore the momentum of the body would be 13500 kg. m/sec

6 0

3 years ago

A block slides down a frictionless plane having an inclination of 15.0°. The block starts from rest at the top, and the length o

nalin [4]

Answer: check the pic

Explanation:

8 0

3 years ago

A crane lifts a 400 N crate full of baked beans 15 m. How much work was done by the crane?

damaskus [11]

Answer:

6000 J

Explanation:

work = F x S

work = 400 x 15

work = 6000 J

3 0

3 years ago