Explanation:
As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.
As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.

So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.
Therefore, concentration of chlorine ions will be calculated as follows.
Concentration of
ions =
= 0.6 mM
Thus, we can conclude that the concentration of chloride ions is 0.6 mM.
I believe it’s 146.06 g/mol
hope this helps! ^^
Answer:
2 CH3COOH + Ba(OH)2 --> Ba(C2H3O2)2 + 2H2O
To make it less clustered, you can use Ac for C2H3O2.
2 HAc + Ba(OH)2 --> Ba(Ac)2 + 2H2O
The acetic acid reacts with the base barium hydroxide to form the salt barium acetate and water.
Explanation:
final answer. C