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Fed [463]
3 years ago
11

How does temperature affect the vapor pressure of a liquid?

Chemistry
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

As the temperature of a liquid increases, the kinetic energy of its molecules also increases. As the kinetic energy of the molecules increases, the number of molecules transitioning into a vapor also increases, thereby increasing the vapor pressure.

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Answer:

D

Explanation:

D is the answer because this is the only one having to do with genetics. Fox's genetics changed because it's environment changed.

6 0
3 years ago
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In a chemical change molecules DO NOT create or break chemical bonds to form a new substance you might be able to observe a chem
vesna_86 [32]

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false

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3 0
3 years ago
A sodium flame has a characteristic yellow color due to emissions of wavelength 589 nm. What is the mass equivalence of one phot
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8 0
3 years ago
Question 3 (1 point)
larisa86 [58]

Answer:

1. Formulae of hydrate is Na₂CO₃.10H₂O

2. Formulae of hydrate is CaSO₄.2H₂O

Explanation:

Q1. Mass of hydrated salt = 8.50 g mass

mass of anhydrous salt = 7.26 grams

mass of water lost = 1.24

Formula of hydrated salt = Na₂CO₃.xH₂O

Formula of anhydrous salt = Na₂CO₃

Molar mass of anhydrous salt is obtained as below where Na = 23, C = 12, O = 16, H = 1

Molar mass of Na₂CO₃ = (23 *2 + 12 + 16 * 3) = 106 g

molar mass of water = (1 *2 + 16) = 18 g

Mole ratio of Na₂CO₃ to H₂O = 7.26/106 : 1.24/18

Mole ratio of Na₂CO₃ to H₂O = 0.0068 : 0.068

Mole ratio of Na₂CO₃ to H₂O = 1 :10

Therefore, formulae of hydrate is Na₂CO₃.10H₂O

Q2.  Mass of hydrated salt = 60.98 g mass

mass of anhydrous salt = 48.23 grams

mass of water lost = 12.75

Formula of hydrated salt = CaSO₄.xH₂O

Formula of anhydrous salt = CaSO₄

Molar mass of anhydrous salt is obtained as below where Ca = 40, S = 32, O = 16, H = 1

Molar mass of CaSO₄= (40 + 32 + 16 * 4) = 136 g

molar mass of water = (1 *2 + 16) = 18 g

Mole ratio of CaSO₄ to H₂O = 48.23/136 : 12.75/18

Mole ratio of CaSO₄ to H₂O = 0.35 : 0.70

Mole ratio of CaSO₄ to H₂O = 1 : 2

Therefore, formulae of hydrate is CaSO₄.2H₂O

4 0
3 years ago
Read 2 more answers
Determine the [H3O⁺] in a 0.365 M HClO solution. The Ka of HClO is 2.9 × 10^-8.
Agata [3.3K]

The concentration of hydronium ion, [H₃O⁺] =  1.3 × 10⁻⁶ M

<u>Explanation:</u>

HClO is a weak acid and it can be ionized and given by the equation as,

HClO + H₂O ⇄  H₃O⁺ + ClO⁻

Ka is given by the expression that the product of the concentration of products divided by the product of the concentration of the reactants.

$ Ka = \frac{[H_{3} O^{+}]\times [ClO^{-}  ]}{[HClO]}  = 2.9 ×10⁻⁸

Consider [H₃O⁺] = [ClO⁻] = x

[HClO] = 0.365 - x

Since Ka is very small, consider x <<<0.365, also it should be ignored.

Ka = 2.9 ×10⁻⁸ = $\frac{x^{2} }{0.365}\\

x² = 2.9 × 10⁻⁸ × 0.365

x = 1.3 × 10⁻⁶ M

Thus we can conclude 3rd Option as correct answer

4 0
3 years ago
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