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ASHA 777 [7]
3 years ago
10

What characteristic is descriptive of a solution?

Chemistry
1 answer:
Snezhnost [94]3 years ago
8 0
A solution is a mixture of two or more substances combined so that it is uniform, which means you cannot see the components. <span />
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Why is paper chromatography used for amino acids
vivado [14]

<em>Paper chromatography is especially useful in characterizing amino acids. The different amino acids move at differing rates on the paper because of differences in their R groups.</em>

5 0
2 years ago
Manual says that he has reduce the amount of thermal energy in a cup of hot chocolate without lowering the temperature.How is th
ANEK [815]
Friction. It transforms other forms of energy into thermal energy
7 0
3 years ago
Mr. Chem S. Tree added water to 250. ML of a 2.50 M NaOH solution, until the final volume was 500. ML. What is the new molarity
tresset_1 [31]

Answer:

molarity of diluted solution = 1.25 M

Explanation:

Using,          

C1V1 (Stock solution) = C2V2 (dilute solution)

given that

C1 = 2.50M

V1 = 250ML

C2 = ?

V2 = 500ML

2.50 M x 250 mL = C2 x 500 mL

C2 = (2.50 M x 250 mL) / 500 mL

C2 = 1.25 M

Hence, molarity of diluted solution = 1.25 M

4 0
3 years ago
A gallon of water has a mass of 3.79 kg. how many moles of water (18.02 g/mol) is this?
garik1379 [7]
First, we will convert the mass of the gallon to grams:
a gallon of water has a mass of 3.79 * 1000 = 3790 grams of water

number of moles can be calculated using the following rule:
number of moles = mass / molar mass
Therefore,
number of moles = 3790 / 18.02 = 210.32 moles
3 0
3 years ago
Read 2 more answers
You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
          = 7.55 - 1.95 = 5.6 
5 0
3 years ago
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