Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate Glyceraldehyde 3-phosphate + DHAP
For the given reaction, is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T =
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = M
Glyceraldehyde 3-phosphate = M
DHAP = M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient =
Q =
=
Now, we will calculate the value of as follows.
=
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.
O is a blood donor
AB receiver
Answer:
1.196 M NaOH
Explanation:
Molarity = moles/Volume (L)
moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH
Volume solution = 250 mL = 0.250L
M = 0.299/0.250=1.196 M NaOH
Balanced chemical reaction:
2NaCl(aq) + Hg₂(C₂H₃O₂)₂(aq) → Hg₂Cl₂(s) + 2NaC₂H₃O₂<span>(aq).
</span>NaCl - sodium chloride.
Hg₂(C₂H₃O₂)₂ - mercury(I) acetate.
NaC₂H₃O₂ - sodium acetate.
Hg₂Cl₂ - mercury(I) chloride or <span>mercurous chloride</span>, low solubility in water.
Oxidation number of sodium is +1 and for mercury is also +1.
The radii of atoms is increasing down the group.
If we look at the group 2, we will see the the lowest element is Ra. It has largest atomic radius and it has to have largest ionic radius.