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ASHA 777 [7]
3 years ago
10

What characteristic is descriptive of a solution?

Chemistry
1 answer:
Snezhnost [94]3 years ago
8 0
A solution is a mixture of two or more substances combined so that it is uniform, which means you cannot see the components. <span />
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For the reaction 2 NO(g) + 2 H2(g) =&gt; N2(g) + 2 H2O(g) the following data were collected. What is the rate law for this react
harkovskaia [24]

<u>Answer:</u> The rate law expression for the given reaction is written below.

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(g)

Rate law expression for the reaction:

\text{Rate}=k[NO]^2[H_2]^2

Hence, the rate law expression for the given reaction is written above.

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3 years ago
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2 years ago
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Elements in the periodic table are listed in order of their -----​
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In numerical order left to right, they are arranged by the number of protons in the nucleus of a single atom of each element

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What is the mass of 25 Liters of nitrogen dioxide gas?
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3 years ago
A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam
Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0
3 years ago
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