Answer:
<h2>288 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 12 × 24
We have the final answer as
<h3>288 kg.m/s</h3>
Hope this helps you
Answer:
A2/A1 = 9
V2/V1 = 27
Explanation:
Area of Sphere 1; A1 = 4πr²
Volume of Sphere 1; V1 = (4/3)πr³
Area of Sphere 2; A2 = 4π(3r)² = 9*4πr²
Volume of Sphere 2; V2 = (4/3)π(3r)³ = 27*(4/3)πr³
Thus;
A2/A1 = 9*4πr²/4πr² = 9
V2/V1 = [27*(4/3)πr³]/[(4/3)πr³] = 27
Answer:
In the double-entry system, transactions are recorded in terms of debits and credits. Since a debit in one account offsets a credit in another, the sum of all debits must equal the sum of all credits.
Explanation:
Answer:
b) The ball is a freely falling body for the duration of its flight.
Explanation:
When an object is thrown upwards, it moves against the direction of gravity. Its velocity decreases with respect to its motion, and zero at the maximum height. After which it falls back to the surface of the earth.
Since the ball moves initially against the force of gravity, its acceleration would be -9.8 m/
at its highest point. Thus since acceleration is constant, the ball is a freely falling body for the duration of its flight.
Answer:
A. 54.88m/s.
B. 153.66m
Explanation:
Data obtained from the question include:
Time (t) = 5.6 secs
A. Determination of the skydiver's downward velocity.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Velocity (v) =..?
v = gt
v = 9.8 x 5.6
v = 54.88m/s
Therefore, the skydiver's downward velocity is 54.88m/s
B. Determination of the height below the helicopter.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Height (H) =..?
H = ½gt²
H = ½ x 9.8 x 5.6²
H = 153.66m
Therefore, the height below the helicopter when the parachute opens is 153.66m.