Answer:
Explanation:
Cross sectional area of post = 3.14 x(10.5)² x 10⁻⁴ = 346.18 x 10⁻⁴ m²
Weight = mg = 8300 x 9.8 = 8.134 x 10⁴ N
Stress = weight / area
= 8.134 x 10⁴ / (346.18 x 10⁻⁴)
23.49 x 10⁵ N / m²
Strain = stress / modulus of elasticity of steel
modulus of elasticity = 190 x 10⁹ Pa
strain = Stress \ young modulus
=![\frac{23.49\times10^5}{190\times10^9}](https://tex.z-dn.net/?f=%5Cfrac%7B23.49%5Ctimes10%5E5%7D%7B190%5Ctimes10%5E9%7D)
= 12.36 x 10⁻⁶
strain = change in length / original length
change in length = original length x strain
= 2.7 x 12.36 x 10⁻⁶
= 33.372 x 10⁻³ mm
.033 mm.
Answer:
d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.
Explanation:
a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.
It has negative acceleration in the negative x-direction.
b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.
It has a positive acceleration in the negative x-direction'
c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.
It has a positive acceleration in opposite direction.
e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
It has a positive acceleration only in opposite direction .
Answer:
look it up
Explanation:
An electrical shock is received when electrical current passes through the body. ... Whenever two wires are at different voltages, current will pass between them if they are connected. Your body can connect the wires if you touch both of them at the same time. Current will pass through your body.
I believe the answer greater than
Answer:
i took g = 9.8m/s
A. 1.16secs
B. 2.32secs
C. 6.57m
D. 57.91m
Explanation:
A. How long does the Missile take to reach ot peak?
Time taken (t) =( U²Sin (angle) )/g
u = initial velocity = 25m/s
angle given = 30°
g = acceleration due to gravity = 9.8m/s²
t = U² x Sin (angle) / g
t = 25² x Sin(30)/9.8
t = 1.61secs
B. How long is the missile in the air in total?
T = 2t
T = 2 x 1.61 = 2.32 secs
C. what maximum Height does the missile reach?
- Maximum height = U²Sin²(angle) / 2g
- M.H =25² x Sin(30)² / 2 x 9.8
- M.H=6.57m
- Maximum height= 6.57m
D. How far does the missile travel Horizontally?
- Range = U²2Sin(angle)/g
- Range = 25² x 2 x Sin(30) / 9.8
- Range = 57.91m